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2 years ago

I need some serious help rn, i got stuck

Mathematics

2 answers:

nordsb [41]2 years ago

7 0

Answer:

I think it is add 11 both sides? If it is wrong i am sooooo sorry

Step-by-step explanation:

bonufazy [111]2 years ago

7 0

The first step is to add 3 to both sides then add 11 to both sides then subtract 11 from both sides then divide 3 on both sides I’m pretty sure I’m sorry if I’m wrong

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Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim

vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

$2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}$

Dividing we get,

$2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}$

Adding, we have,

$2 { h } 54 \text { min }=2.9 {h}$

Thus, the total time taken by Joshua is $2.9 {h}$

To determine the average speed we use the formula,

$speed=\frac{distance}{time}$

where $distance=7250$ and $time=2.9$

Hence, substituting the values we have,

$speed=\frac{7250}{2.9}$

Dividing, we get,

$speed=2500$

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0

3 years ago

Help pls?? will give brainilest <3

N76 [4]

Answer:

The y = 0.5 the x = 1

Step-by-step explanation:

The y = 0.5 the x = 1

6 0

3 years ago

Read 2 more answers

I WILL AWARD BRAINLIEST!!!! PLEASE HELP!!!!!

Dahasolnce [82]

as AB || DE then

angle BAE = angle AED

so angle AED = 70

as AD = AE then

angle AED = angle ADE = 70

now in a triangle

angle DAE + Angle ADE + angle AED = 180

angle DAE + 70 + 70 = 180

angle DAE = 180 - 140 = 40

4 0

3 years ago

What would this equal too look at the screen shot

jekas [21]

Given:

The figure of two parallel lines MP and QS.

A transversal line KL interests the two parallel lines.

$m\angle KNM =146^\circ$

To find:

The $m\angle KRQ$ .

Solution:

If a transversal line intersect the two parallel lines, then the corresponding angles are congruent and their measures are equal.

In the given figure $\angle KRQ$ and $\angle KNM$ corresponding angles. It means their measures are equal.

$m\angle KRQ=m\angle KNM$

$m\angle KRQ=146^\circ$

Therefore, $m\angle KRQ=146^\circ$ .

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3 years ago

Graph the equation y = -3x on a graph

Dafna1 [17]

Put a dot on the -3 from the y-axis and draw a straight line from left to right.

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3 years ago