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2 years ago

I need some serious help rn, i got stuck

Mathematics

2 answers:

nordsb [41]2 years ago

7 0

Answer:

I think it is add 11 both sides? If it is wrong i am sooooo sorry

Step-by-step explanation:

bonufazy [111]2 years ago

7 0

The first step is to add 3 to both sides then add 11 to both sides then subtract 11 from both sides then divide 3 on both sides I’m pretty sure I’m sorry if I’m wrong

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The length of a shadow of a building is

timofeeve [1]

H^2=x^2+y^2

35^2=29^2+y^2

y^2=35^2-29^2

y^2=384

y=√384

y≈19.60 m (to the nearest hundredth of a meter, or nearest centimeter)

6 0

3 years ago

Ray Barbee, a radio announcer, is single, earns $300.74 weekly, and claims 2 allowances.

scZoUnD [109]

Answer: https://prezi.com/p/wqgmakneo7_m/net-pay/

Step-by-step explanation: watch and youll get an answer

7 0

2 years ago

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

2 years ago

HELP!!! 15 points. picture below

vlada-n [284]

Step-by-step explanation:

$\sin( \alpha ) = \frac{ \sqrt{5} }{3} \\ \alpha = 48.19 \: degrees \\ \cos( \alpha ) = \frac{2}{3}$

7 0

3 years ago

Read 2 more answers

If 12 less than 4 times a number is 8, the number is 5. Write a different sentance where the unknown number is also 5.

anastassius [24]

Two times a number minus 4 is six. (2*5-4=6)

7 0

3 years ago

Read 2 more answers