A comfortable walking pace is about 3 miles per hour.How far a person walk in a 4 hours at a pace of 3 miles per hour. Make a ta
1 answer:
You might be interested in
Answer:
2x +12y = -63 . . . in standard form
y = -1/6x -21/4 . . . in slope-intercept form
Step-by-step explanation:
It is useful to find the midpoint of the segment. That is the average of the end points:
M = ((-1, -2) +(-2, -8))/2 = ((-1-2)/2, (-2-8)/2) = (-3/2, -5)
It is also useful to find the changes in coordinates from B to A:
Δ = A-B = (-1-(-2), -2-(-8)) = (1, 6)
From here, there are a couple of ways you can write the equation of the perpendicular line.
__
One way is to use the Δ values to compute the slope of the segment. The perpendicular line will have a slope that is the negative reciprocal of that.
Δy/Δx = 6/1 = 6
m = -1/6 . . . . . slope of the perpendicular line
Now we have a point and a slope for the desired line, so we can use a point-slope form of the equation for a line:
y = m(x -h) +k
y = (-1/6)(x -(-3/2)) +(-5)
y = (-1/6)x -21/4 . . . . . . . . eliminate parentheses; point-slope form
__
Another way to write the perpendicular line is to use the Δ values directly as coefficients in the standard form equation:
Δx(x -h) +Δy(y -k) = 0
1(x -(-3/2)) + 6(y -(-5)) = 0 . . . substitute values
x +6y +31.5 = 0 . . . . . . . . . . .collect terms
2x +12y = -63 . . . . . . . . . . . . multiply by 2, put in standard form
Refer to the diagram shown below.
The value of z that yields the expected central area takes into account the excluded areas at both tails.
Half the tail area is α/2 = 0.08/2 = 0.04.
The central area is 1 - 0.04 - 0.04 = 0.92.
From standard normal tables, obtain
z(α/2) = 1.75
Answer: 1.75
The value of z that yields the expected central area takes into account the excluded areas at both tails.
Half the tail area is α/2 = 0.08/2 = 0.04.
The central area is 1 - 0.04 - 0.04 = 0.92.
From standard normal tables, obtain
z(α/2) = 1.75
Answer: 1.75