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ira [324]
3 years ago
10

What is the solution to this system of linear equations? x y = 4 x − y = 6.

Mathematics
1 answer:
nexus9112 [7]3 years ago
5 0

Answer:

Step-by-step explanation:x y = 4 x - y = 6 = get you some b1tc1es

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Please Help! A car traveling at 15 m/s starts to decelerate steadily. It comes to a complete stop in 10 seconds. What is it's ac
Eva8 [605]

Answer:

initial velocity = 15 m/s

final velicity = 0 m/s

time required = 10sec

Formula is V = U + at

0 = 15 + a 10

-15 ÷ 10 = acc

acc = - 1.5 m/s^2

plz give branlist

6 0
3 years ago
A taxi charges $2.50 for the first mile and $0.40 for each mile after that. The expression below shows how to find the total cos
Svet_ta [14]

The expression which shows the total cost is 2.50+0.4x and the cost of riding 20 miles is $10.50.

Given a taxi charges $2.50 for the first mile and $0.40 for each mile

We are required to make an expression showing total cost and total cost of a 20 mile ride.

let the miles ride by tax be x.

Total cost of the product or service=Number of units*price of one units.

We have been given that $2.50 is fixed so we will not multiply our variable charge with $2.50 and multiply 0.40 with x.

So,the expression showing looks like 2.50+0.40x.

Now to find the cost when taxi travels 20 miles, we have to put x=20,

Cost=2.50+0.40*20

=2.50+(40*20)/100

=2.50+800/100

=2.50+8

=$10.50

Hence the expression which shows the total cost is 2.50+0.4x and the cost of riding 20 miles is $10.50.

Learn more about expression at brainly.com/question/723406

#SPJ4

6 0
2 years ago
I will give thanks and five stars to the person that helps me.
weqwewe [10]

Answer:

1. \:  \: x  >   - 16 \\ 2. \:  \: x  >   - 16 \\ 3. \:  \: x >16

4 0
3 years ago
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For what value of x do the functions f(x)=−52x+4 and g(x)=−12x−4 have the same output?
PSYCHO15rus [73]
- 52 x 1/5 + 4 = - 6.4
-12 x 1/5 - 4 = -6.4
The answer is 1/5
8 0
3 years ago
What's the difference between 8:47 and 7:47 ​
lbvjy [14]

Answer:

1 hour apart

Step-by-step explanation:

6 0
3 years ago
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