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2 years ago

If the lengths of the legs triangle are 18 inches and 24 inches, what is the length of the hypotenuse?

Mathematics

2 answers:

frez [133]2 years ago

7 0

Answer:

The length of the hypotenuse = 25 inches

Natalka [10]2 years ago

3 0

Answer:

30 inches

Step-by-step explanation:

Use the Pythagorean theorem.

a² + b² = c²

18² + 24² = c²

324 + 576 = c²

900 = c²

c = √900

c = 30

Answer: 30 inches

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F(x) = 17 - 2x Find f(a + 7)

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Answer:

-2a + 3

Step-by-step explanation:

We can substitute a + 7 for x:

f(a + 7) = 17 - 2(a+7) = 17 - 2a - 14 = -2a + 3

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3 years ago

Please help ASAP If f(x) = x^2-6x+2 and g(x) =sqrt x find a.) (fog) (x) b.) (gof) (-2)

Rudik [331]

$\large\begin{array}{l} \left\{\!\begin{array}{l} \mathsf{f(x)=x^2-6x+2}\\ \mathsf{g(x)=\sqrt{x}}\\ \end{array}\right. \end{array}$

$\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}$

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$\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}$

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Tags: composite function composition evaluate algebra

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3 years ago

Factor 12q^2+34q-28. Include list of factors.

Misha Larkins [42]

Answer:

2(2q+7)(3q-2)=0

Step-by-step explanation:

lets set up the equation equal to 0:

12q^2+34q-28=0

now, lets factor:

2(6q^2+17q-14)=0

2(2q+7)(3q-2)=0

now, lets find the solutions:

2q+7=0

2q=-7

q=-3.5

3q-2=0

3q=2

q=2/3

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3 years ago

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