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ExtremeBDS [4]
3 years ago
12

What is the best first step in solving the equation 3 + = 5? Subtract 3 from both sides. Find the cube of . Cube both sides of t

he equation. Subtract 5 from both sides.
Mathematics
2 answers:
cluponka [151]3 years ago
8 0
Subtract 3 from both sides
Paul [167]3 years ago
4 0
Subtract 3 from both sides
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The x-intercept of the graph is the x-point where graph touches the x-axis. ... Here graph touches the x-axis two times. (c) (–1, 2) and (1, 0): x-intercept are -1 and -1.
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3 years ago
Which expression is equivalent to the given expression?<br> (-4ab)3
vampirchik [111]

Answer:

-64a³b³

Step-by-step explanation:

please like and Mark as brainliest

6 0
4 years ago
A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
3 years ago
Dadas las funciones f(x) = x + 3, g(x)= x(cuadrada)+ 5x + 6,r(x) = x+2, s(x) = x(cuadrada) - 3x - 10
Aleksandr [31]
So the answer is D hope this would help you

5 0
3 years ago
E
IgorLugansk [536]

Answer:

10.35 miles in 1 hout

Step-by-step explanation:

I'm Sorry if this wrong.

5 0
3 years ago
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