Question

AB is congruent to DE because segment DE was constructed so that DE = AB. BC is congruent to EF because segment EF was constructed so that EF = BC. Since ADEF is a right triangle, DE+ EF? = DF? by the We are given that AB + BC2 = AC? Since DE = AB and EF = BC, DE2 + EF2 = AC? by the Also, DF2 = AC2 by the Taking the square root of both sides of the equation gives DF = AC. So, AC is congruent to DF by the definition of congruence. Applying the AABC - ADEF. By CPCTC, ZB _ZE. Therefore ZB is a right angle and AABC is a right triangle.

Answer 1

DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

Congruent shape

Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.

Given that DE = AB and BC = EF.

In right triangle DEF, using Pythagoras:

DF² = DE² + EF²

Also, In right triangle ABC, using Pythagoras:

AC² = AB² + BC²

But DE = AB and EF = BC, hence:

AC² = DE² + EF²

AC² = DF²

Taking square root of both sides, hence:

AC = DF

Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

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