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Oksi-84 [34.3K]
3 years ago
10

Question 2 There are 10 balls in a bag They are red or blue or yellow There are twice as many blue balls as red balls. There are

more red balls than yellow balls. Atoll is taken at random from the bas. fa in the table to show the probability of taking each colour Red Blue Yellow Probably (3 marks)​
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
4 0

Your intuition is sound, but it has to be based on some prior expectation about the balls in the bag.

For example, if you thought before you drew the blue ball that the bag was equally likely to contain any number of blue balls from zero to 10, after pulling it out you think that the probability of k blue balls remaining in the bag is (k + 1) / 55 for k = 0 to 9. That means the expected number of blue balls is now 6. Before you drew the ball the expected number was 5, so even though there is one fewer blue ball in the bag, you expect there to be one more.

But suppose instead that before you drew the first ball you thought there was a 50/50 chance of zero blue balls and one blue ball. After the draw you know there are no blue balls left, so your expectation went down from 1/2 to zero

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Whoever answers this first gets brainliest<br> Pls help ASAP
Mandarinka [93]

Answer:

Terminating goes to 3

Repeating goes to 4

Rational goes to 1

Irrational goes to  2

7 0
3 years ago
Read 2 more answers
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

        199

        175

        ----

          24

         ----

last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

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3 years ago
The point (-2, 4) is on the line given by which equation below
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It would be B because-2 is x and 4 is y
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5.372 divided by 2 = please help
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The answer is 2.686, and i am writing these extra characters to pass the 20 character qualifications.
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katen-ka-za [31]
First : x=-5-y and then put x in the phrase above
7 0
3 years ago
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