Answer:
x = 2 ± 2 sqrt(5)i
Step-by-step explanation:
(x – 2)^2 + 20 = 0
Subtract 20 from each side
(x – 2)^2 + 20 -20=0 -20
(x – 2)^2 =- 20
Take the square root of each side
sqrt((x – 2)^2) =±sqrt(- 20)
x-2 = ±sqrt(- 20)
We know sqrt(ab) = sqrt(a) sqrt(b)
x-2 = ±sqrt(- 1) sqrt(20)
We know the sqrt (-1) = i
x-2 = ±i sqrt(4*5)
x-2 = ±i sqrt(4) sqrt(5)
Add 2 to each side
x-2+2 = 2 ±i sqrt(4) sqrt(5)
x = 2 ±i 2 sqrt(5)
x = 2 ± 2 sqrt(5)i
Answer:
Step-by-step explanation:
<u>There are two roots:</u>
<u>The function is:</u>
- f(x) = (x - 3)(x - 2)
- = x² - 5x + 6
All you need to do is add 37+16 and it will be equivalent to 53
5x-1 is greater than or equal to -11
Y = mx + b
slope(m) = 4
(-3,-1)...x = -3 and y = -1
now we sub...we r looking for b, the y int.
-1 = 4(-3) + b
-1 = -12 + b
-1 + 12 = b
11 = b
so ur equation is : y = 4x + 11
