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tamaranim1 [39]
2 years ago
12

The range is the set of____ 1.ordered pairs 2.second coordinates 3.first coordinates

Mathematics
1 answer:
suter [353]2 years ago
7 0

Answer:

2. Second Coordinates

Step-by-step explanation:

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Answer ASAP
Elenna [48]

Answer:

All of the following have the same value except <u>6-9.</u>

Step-by-step explanation:

9+(-6)=POSITIVE 3

9-6=POSITIVE 3

-6-(-9)=POSITIVE 3

6-9=NEGATIVE 3

Hope this Helps

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7 0
3 years ago
Read 2 more answers
25 people apply for a job, 15 men and 10 women. they will hire 10 people, with 40% of them women. how many different staff selec
luda_lava [24]
So if they'll hire 40% women, and they're hiring 10 people, this means that they'll hire 4 women. And the rest of the people are all men, or 6 of them. 

So basically, you can think of this like a tree, taking the men's side first, with 15 possible hires in the beginning, and then 14 more stemming off of that, and then 13 more stemming of those, etc.

So basically it would be:

15 * 14 * 13 * 12 * 11 * 10

Because there are four spots for men, and there were 15 men, and after every hire, there will be one less applicant, because there would've been one hire instead.

So;

15 * 14 * 13 * 12 * 11 * 10 = 3603600

And then women just do the same thing.

10 * 9 * 8 * 7 = 5040

Then just multiply those together as well.

18162144000 is your final answer.

5 0
3 years ago
Simplify the expression using the distributive property:<br> 5 (2x – 3y + 4)
Anni [7]

Apply the distributive property. 5 (2x) +5 (−3y) + 5 ⋅ 4

Multiply 2 by 5

10x + 5 ( − 3y ) + 5 ⋅ 4

Multiply  −3 by 5     10x − 15y + 5 ⋅ 4

Multiply  5 by 4

Answer: 10x −15y + 20

Tip: The sign   "⋅"  means multiply

8 0
3 years ago
assume the substance has a half-life of 11 years and the initial amount is 126 grams.How long will it be until only 15 % remains
Mumz [18]
(126) times (1/2 to the x/11 power) = 15% times 126

(1/2) to the x/11 power = 0.15

Take the log of both sides :

(x/11) times log(1/2) = log(0.15)

Multiply both sides by 11 :

'x' times log(1/2) = 11 x log(0.15)

Divide both sides by " log(1/2) " :

x = 11 x log(0.15)/log(1/2) = <em><u>30.107 years</u></em> (rounded)

That's the time it takes for <em><u>any-size</u></em> sample of this substance
to decay to 15% of its original size.


5 0
3 years ago
Of the 45 animals on the farm, there are only pigs and chickens. The animals have a total of 124 legs. How many pigs and how man
Bess [88]

Answer:

on \: this \: farm \: there \: are \to \\  \underline{ \boxed{17 \: pigs }}\:  \\  and \\  \underline{ \boxed{28 \:chickens}}

Step-by-step explanation:

\\  \underline{ \boxed{solution \: to \: question \:  \boxed{ A}}} \\ \\ let \: the \: pigs \: be \to \: p \\ let \: the \: chicks \: be \to \: c \\let \: the \: total \: animals \: be \to \: 45 \\  hence \to \\ p + c = 45.......eq(1) \\ since \: chickens \: have \: two \: legs : \\  while \: pigs \: have \: four \: legs : \\ let \: animals \: with \: 2 \: legs \: be \to \: 2c \\ let \: animals \: with \: 4\: legs \: be \to \: 4p \\ the \: total \: number \: of \: animal \: legs  = 124 \\ hence \to \\ 4p + 2c = 124..........eq(2) \\ therefore \: the \: system \:  of \:  equations \: \\   to  \: describe  \: the  \: situation \: is \to \\ \\  p + c = 45 \\ 4p + 2c = 124 \\  \\  \\ \underline{ \boxed{solution \: to \: question \:  \boxed{B }}} \\  \\  \\ we \: could \: apply \: any \: of \: the \: simultanious \\  principles \to \\ here : am \: appling \: the \: elimination \: method   \to \\ p + c = 45 \\ 4p + 2c = 124  \\ to \: elimnate \: one \: varaible \: we \: multiply \: by \to \\ (4) \times p + c = 45 \\ (1) \times 4p + 2c = 124  \\ hence \to \\   - \frac{4p + 4c = 180}{4p + 2c = 124}  \\next \to \\   2c = 56 \\ c =  \frac{56}{2}  \\ \boxed{ c = 28} \\ lets \: work \: for \: p \to \\ p + c = 45 \\ p + 28 = 45 \\ p = 45 - 28 \\  \boxed{p = 17}

6 0
3 years ago
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