To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above:
- The <span>spherical bubble gum ball is at the bottom
- The radius of the cone is 1.5 inches, and its height is 3 inches.
- The diameter of the bubble gum ball is 0.5 inches.
2. Therefore, you must apply the formula for calculate the volume of a sphere to find the volume of the bubble gum ball:
Vs=4</span>πr^3/3
r is the radius (r=0.5 inches/2=0.25 inches)
Vs=4π(0.25 inches)^3/3
Vs=0.065 inches^3
3. The volume of the cone is:
Vc=πr^2h/3
r is the radius of the cone (r=1.5 inches)
h is the height (h= 3 inches)
Vc=π(1.5 inches)^2(3 inches)/3
Vc=7.06 inches^3
W<span>hat is the closest approximation of the volume of the cone that can be filled with flavored ice?
Vt=Vc-Vs
Vt</span>≈7.00 inches^3
Given the coordinates of two points, P1 and P2, the distance formula between these two points is deduced.
d = root ((x2-x1) ^ 2 + (y2-y1) ^ 2)
To find the area of the figure we must first find the area of the rectangle and add the area of the parallelogram.
rectangle area
A = (L) * (w)
L = root ((- 6-2) ^ 2 + (- 1-1) ^ 2) = 8.25
w = root ((- 6 - (- 5)) ^ 2 + (- 1 - (- 5)) ^ 2) = 4.12
A = (8.25) * (4.12) = 33.99
Parallelogram area
A = (b) * (h)
b = root ((3-3) ^ 2 + (3 - (- 3)) ^ 2) = 6
h = root ((3-2) ^ 2 + (3-3) ^ 2) = 1
A = (6) * (1) = 6
The total area is then
Atotal = 33.99 + 6 = 39.99 units ^ 2
Answer
the area of this figure is 39.99 units ^ 2
Answer:
a) There are 10 different samples of size 2.
b) See the explanation section
c) See the explanation section
Step-by-step explanation:
a) We need to select a sample of size 2 from the given population of size 5. We use combination to get the number of difference sample.

b) Possible sample of size 2:
Peter Hankish 8 Connie Stallter 6 Juan Lopez 4 Ted Barnes 10 Peggy Chu 6
- Peter Hankish and Connie Stallter ( Mean = (8 + 6)/2 = 14/2 = 7)
- Peter Hankish and Juan Lopez (Mean = (8 + 4)/2 = 12/2 = 6)
- Peter Hankish and Ted Barnes (Mean = (8 + 10)/2 = 18/2 = 9)
- Peter Hankish and Peggy Chu (Mean = (8 + 6)/2 = 14/2 = 7)
- Connie Stallter and Juan Lopez (Mean = (6 + 4)/2 = 10/2 = 5)
- Connie Stallter and Ted Barnes (Mean = (6 + 10)/2 = 16/2 = 8)
- Connie Stallter and PeggyChu (Mean = (6 + 6)/2 = 12/2 = 6)
- Juan Lopez and Ted Barnes (Mean = (4 + 10)/2 = 14/2 = 7)
- Juan Lopez and Peggy Chu (Mean = (4 + 6)/2 = 10/2 = 5)
- Ted Barnes and Peggy Chu (Mean = (10 + 6)/2 = 16/2 = 8)
c) The mean of the population is:

Comparing the mean of the population and the sample; we can say that most of the 2-size sample have their mean higher than that of the population sample. And the variation with the mean is not much. Some sample have their mean greater than population mean, while some sample have their mean greater than the population mean.
Answer:
2
- 5
Step-by-step explanation: