A. <span>the probability of a false negative test results
This corresponds to
P (false | negative) = P (false) x P (negative)
= (1 - P(true)) (1 - P(positive))
= (1 - 0.75)(1 - 0.88)
= 0.03
b. </span><span>he probability of a false positive test result
= (1 - 0.75) (0.88)
= 0.22</span><span />
Figure out and understand how exactly you learn and process things and information then simply take it from there.
Read the books given to you and Bing/Google search things of your questioning. Read over the things you will be tested on, Get some nice study music on (something you enjoy nothing to genetic), read your books, quiz yourself to make sure you understand and take these ideas and create your own solutions through figuring out how you'd like to get ready.
Answer:
I guess the application method by hands is more harmful. As pesticides are some sort of chemical substances which are used to kill insects and other sort of pests in any kind of plant. And we also know that pesticides are chemical substances.So when pesticides are typically applied by hands it can damage your palm skin.After applying pesticides you wash your hands. But, Do you know that even after washing little amount of pesticides are left on your palm?? And by using that hands you cook food then eat it. Then, you will fall sick as well as your family members. So, isn't it harmful to apply pesticides by using your hands??
Donkey. They eat paper BTW.
Solution. To check whether the vectors are linearly independent, we must answer the following question: if a linear combination of the vectors is the zero vector, is it necessarily true that all the coefficients are zeros?
Suppose that
x 1 ⃗v 1 + x 2 ⃗v 2 + x 3 ( ⃗v 1 + ⃗v 2 + ⃗v 3 ) = ⃗0
(a linear combination of the vectors is the zero vector). Is it necessarily true that x1 =x2 =x3 =0?
We have
x1⃗v1 + x2⃗v2 + x3(⃗v1 + ⃗v2 + ⃗v3) = x1⃗v1 + x2⃗v2 + x3⃗v1 + x3⃗v2 + x3⃗v3
=(x1 + x3)⃗v1 + (x2 + x3)⃗v2 + x3⃗v3 = ⃗0.
Since ⃗v1, ⃗v2, and ⃗v3 are linearly independent, we must have the coeffi-
cients of the linear combination equal to 0, that is, we must have
x1 + x3 = 0 x2 + x3 = 0 ,
x3 = 0
from which it follows that we must have x1 = x2 = x3 = 0. Hence the
vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
Answer. The vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
