Question

A computer’s memory is composed of 8k words of 32 bits each. How many bytes does this memory contain?.

Answer 1

Answer:

32 000 bytes

Explanation:

Answer 2

Answer:

The minimum number of bits necessary to address 8K words is 13.

Explanation:

You have the number of words to address that is 8000 words, a word is the smallest addressable memory unit.

8000 words can be addressed with 2 units. Now you have to find the value of n that approximates to the number of words.

2² = 4

24

16

27 = 128

210 1024

212 = 4096

213

8192

So you can see that 13 bits are needed to address 8K words.