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MakcuM [25]
3 years ago
15

Can someone help, thanks!​

Mathematics
1 answer:
Marina86 [1]3 years ago
4 0

Answer:

16, 10

Step-by-step explanation:

There are 4 quarts in a gallon, so 4 gallons has 16 qt.

There are 2 pints in a quart, so 5 quarts has 10 pt.

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Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra
katen-ka-za [31]

You made a mistake with the probability p_{j}, which should be p_{i} in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer j, is given by:

(1) \frac{p_{j} }{1-d_{i}p_{i}  } , if j \neq i, and

(2) \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  } , if j = i.

so we can say:

A is the event that you search drawer i and find nothing,

B is the event that you search drawer i and find the paper,

C_{k}  is the event that the paper is in drawer k, k = 1, ..., n.

this gives us:

P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}

P(A) = 1 - P(B) = 1 - d_{i} p_{i}

Solution to Part (1):

if j \neq i, then P(A \cap C_{j} ) = P(C_{j} ),

this means that

P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)}  = \frac{P(C_{j} )}{P(A)}  = \frac{p_{j} }{1-d_{i}p_{i}  }

as needed so part one is solved.

Solution to Part(2):

so we have now that if j = i, we get that:

P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}

remember that:

P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}

this implies that:

P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )

so we just need to combine the above relations to get:

P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  }

as needed so part two is solved.

8 0
4 years ago
Calibrating a scale:
lana66690 [7]

Answer:

We conclude that the calibration point is set too high.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ =  1000 grams

Sample mean, \bar{x} =  1001.1 grams

Sample size, n = 50

Alpha, α = 0.05

Population standard deviation, σ = 2.8 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 1000\text{ grams}\\H_A: \mu > 1000\text{ grams}

We use One-tailed(right) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{ 1001.1 - 1000}{\frac{2.8}{\sqrt{50}} } = 2.778

Now, z_{critical} \text{ at 0.01 level of significance } = 2.326

Since,  

z_{stat} > z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. We accept the alternate hypothesis. We conclude that the calibration point is set too high.

6 0
3 years ago
Simplify<br><br> sqrt(3 + 2 sqrt 2) ...?
trasher [3.6K]
The answer is 1 + √2

sqrt(2) is \sqrt{2}
sqrt(3 + 2 sqrt 2) is \sqrt{3 +2 \sqrt{2} }
Now, let's simplify \sqrt{3 +2 \sqrt{2} }.
We will use square of sum: (a + b)² = a² + 2ab + b²

\sqrt{3 +2 \sqrt{2} } = \sqrt{1+2+2 \sqrt{2} }= \sqrt{1+2 \sqrt{2}+2 }= \\ &#10;= \sqrt{1^{2} +2*1* \sqrt{2} + (\sqrt{2} ) ^{2} } = \sqrt{(1+ \sqrt{2}) ^{2}} =1+ \sqrt{2}
8 0
3 years ago
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A train travels 190 km in 3.0 hours and then 120 km in 2.0 hours. What is its average speed?
melisa1 [442]
The average speed it 310
3 0
3 years ago
Lola dice Argos mi perro tiene 10 kg menos que roco cuantos kilogramos tiene argos
Elena L [17]

Answer:

A=R-10

Step-by-step explanation:

The problem is:

<em>Lola says: Argos, my dog, has 10 kilograms less than Roco. How much kilograms Argos has?</em>

<em />

This problem is about algebraic language. We just need to express the ordinaty language into an equation.

We know the words less means difference. So, let's call A Argos' weight and R Roco's weight. We can expresse the given problem as

A=R-10

Notice that we applied a difference due to the word "less" in the problem.

Therefore, Argo's weight is given by the expression

A=R-10

7 0
3 years ago
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