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Deffense [45]
2 years ago
5

3. An art class charges each student $3 to attend plus a fee for supplies. Today, $20 was collected for the 5 students attending

the class.​
Mathematics
1 answer:
Igoryamba2 years ago
3 0

Answer:

tax =1

Step-by-step explanation:

20=5(3+x)

4=3+x

x=1

x as in tax

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Find the area of a circle with a radius of 6 ft. Round off your answer to one decimal point. (The formula for the area of a circ
butalik [34]

Answer:

Using 3.14   for pi  A = 113.0  ft^2

Using the pi button A = 113.1 ft^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

A = pi ( 6)^2

A = 36 pi

Using 3.14 for an approximation for pi

A = 36(3.14) = 113.04

To 1 decimal

113.0

Using the pi button

A = 113.0973355

A = 113.1

3 0
3 years ago
Write an equation of a circle given the center (-4,4) and radius r=5
Irina-Kira [14]

Answer:

Step-by-step explanation:

Equation of circle: (x - h)² + (y - k)² = r²   where (h,k) is the center.

Center( -4 , 4) and r = 5

(x -[-4])² + (y - 4)²= 5²

(x + 4)² + (y-4)² = 25

x²  + 2*4*x +4²  + y²  - 2*y*4 + 4²  = 25

x²  +8x + 16 + y²  - 8y + 16 = 25

x²  + 8x + y²  - 8y + 16 + 16 -25 = 0

x²  + 8x + y²  - 8y +7 = 0

8 0
3 years ago
Write the set { 1, 3, 7, 15, 31, 63 } in set builder form ​
Sholpan [36]

Answer:

{ x : x = 2^n -1 , n ∈ N}

Where N is the set of natural numbers

Step-by-step explanation:

Mathematically, we can rewrite each term in the set as follows;

1 = 2^1 - 1

3 = 2^2 -1

7 = 2^3 -1

15 = 2^4-1

31 = 2^5-1

63 = 2^6 -1

so we can conclude that the nth term is 2^n -1

So writing this in set builder notation, we have;

{ x : x = 2^n -1 , n ∈ N}

Where N is the set of natural numbers

3 0
3 years ago
Use the identity below to complete the tasks:
quester [9]

Answer:

a=[2q^{2}r]

b=[3s^{2}t]

Step-by-step explanation:

we have

8q^{6}r^{3}+27s^{6}t^{3}

we know that

8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}

27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}

therefore

a=[2q^{2}r]

b=[3s^{2}t]

substitute

a^{3} +b^{3}=(a+b)(a^{2} -ab+b^{2})

[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})

[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])

7 0
3 years ago
Read 2 more answers
Denise buys a tote bag at a gift shop for $12. The same bag is available at Denise’s pharmacy for 2/3 the price she paid at the
liq [111]
It would be 15 because 2/3 of $12 is $8. she has enough money to buy 10 bags from the gift shop which means she has $120. at the pharmacy, $120 would buy her 15 bags.
8 0
3 years ago
Read 2 more answers
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