PART 1.
Going westward:
Distance: 2400 miles
Rate (this is speed): (450-wind_speed) mph
Time: distance / speed = 2400 / (450-wind speed)
Going eastward:
Distance: 2400 miles
Rate (this is speed): (450+wind_speed) mph
Time: distance / speed = 2400 / (450+wind speed)
PART 2
Formula for speed:
speed = distance / time
Now we solve this for time:
time = distance / speed
11h = 2400 / (450+-wind_speed)
+- sign is put because in one case wind increases speed of plane and in other case it decreases speed.
PART 3
To solve for wind_speed we start by rearranging formula so that we have wind_speed on left side:
(450+-wind_speed) = 2400 / 11
(450+-wind_speed) = 218mph
To fly this distance in 11h speed of plane must be 218mph.
The only way to get this solution is if we substract wind speed:
450-wind_speed = 218
wind_speed = 450-218 = 232mph
Answer:
we need a picture of the ghraph
Answer:
y = -4x + 29
Step-by-step explanation:
-3 = -4(8) + b
-3 = -32+b
29=b
An expression to represent this problem would be 2/y-3 as it asks for an expression that shows the answer to three less (meaning 3 will be subtracted from) than the quotient of the expression 2/y.
