Question

Solve 2x-1=3y 5(2x-1)+y=32

Answer 1

Answer:

x = 7/2 (3 1/2), y = 2

Step-by-step explanation:

• $2x - 1 = 3y$
• $10x + y -5=32$

Step 1: Solve 10x + y - 5 for y.

• $10x+y-5-10x=32-10x$ (subtract 10x from both sides)
• $y - 5 = -10x + 32$

• $y-5+5=-10x+32+5$ (add 5 to both sides)
• $y = -10x + 37$

Step 2: Substitute -10x + 37 for y in 2x - 1 = 3y.

• $2x-1=3(-10x+37)$
• $2x - 1 = -30x + 111$ (simplify both sides)
• $2x-1+30x=-30x+111+30x$ (add 30x to both sides)
• $32x-1=111$
• $32x-1+1=111+1$ (add 1 to both sides)
• $32x = 112$
• $32x/32 = 112/32$ (divide both sides by 32)
• $x = 7/2$

Step 3: Substitute 7/2 for x in y = -10x +37.

• $y=-10(7/2) +37$
• $y = -35 + 37$ (simplify both sides)
• $y = 2$ (simplify both sides

Have a lovely rest of your day/night, and good luck with your assignments! ♡

 ~ ren

Answer 2

2x-1=3y would be 1/-3
For 5 (2x-1)+y=32 would be 37/10, if its wrong, forgive me