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valina [46]
2 years ago
11

Which of the following best describes a characteristic of that makes it useful as hereditary material?.

SAT
1 answer:
m_a_m_a [10]2 years ago
7 0
The first choice

Explanation
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Fawn spends hours each week managing staff shifts and schedules, time that you would have to spend on other restaurant operation
Ludmilka [50]

Answer:

nose

Explanation:

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3 0
3 years ago
Calculate the mass of hydrogen in 57. 010 grams of ammonium hydrogen phosphate.
erastovalidia [21]

The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g  

<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>

1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g

<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>

Mass of H = 6H = 6 × 1 = 6 g

<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>

115 g of (NH₄)H₂PO₄ contains 6 g of H.

Therefore,

57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H

Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄

Learn more about mass composition:

brainly.com/question/13531044

4 0
2 years ago
Complete the square:36x=-4x^2-50
bija089 [108]

Answer:

The Answer is the following :

Explanation:

5 0
3 years ago
Read 2 more answers
A survey found that​ women's heights are normally distributed with mean
zheka24 [161]

Answer:

a. 99.30% of the woman meet the height requirement

b.  If all women are eligible except the shortest​ 1% and the tallest​ 2%, then height should be between 58.32 and 68.83

Explanation:

<em>According to the survey</em>, women's heights are normally distributed with mean 63.9 and standard deviation 2.4

a)

A branch of the military requires​ women's heights to be between 58 in and 80 in. We need to find the probabilities that heights fall between 58 in and 80 in in this distribution. We need to find z-scores of the values 58 in and 80 in. Z-score shows how many standard deviations far are the values from the mean. Therefore they subtracted from the mean and divided by the standard deviation:

z-score of 58 in= z=\frac{58-63.9}{2.4} = -2.458

z-score of 80 in= z=\frac{80-63.9}{2.4} = 6.708

In normal distribution 99.3% of the values have higher z-score than -2.458

0% of the values have higher z-score than 6.708. Therefore 99.3% of the woman meet the height requirement.

b)

To find the height requirement so that all women are eligible except the shortest​ 1% and the tallest​ 2%, we need to find the boundary z-score of the

shortest​ 1% and the tallest​ 2%. Thus, upper bound for z-score has to be 2.054 and lower bound is -2.326

Corresponding heights (H) can be found using the formula

2.054=\frac{H-63.9}{2.4}  and

-2.326=\frac{H-63.9}{2.4}

Thus lower bound for height is 58.32 and

Upper bound for height is 68.83

8 0
3 years ago
find a percent of discount for a pair of pants that cost $65 but are now on sale for $42.25. (please show understandable work)​
QveST [7]

Answer:

What is the real meaning of this questions

8 0
2 years ago
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