The proportion of field mice weighing more than 33 grams in the distribution will be about 0.2275
- Mean, μ = 25 grams
- Standard deviation, σ = 4 grams
- Score, X = 33 grams
We need to calculate the P(Z > Zscore)
Recall :
Zscore = (X - μ) ÷ σ
For X > 33 :
Zscore = (33 - 25) ÷ 4 = 2
Therefore, the probability would be expressed as :
P(Z > 2) = 1 - P(Z < 2)
From the normal distribution table :
P(Z < 2) = 0.97725
Therefore,
P(Z > 2) = 1 - 0.97725 = 0.02275
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Hopefully this helped :)
