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3 years ago

Enter the missing numbers in the boxes to complete the table of equivalent ratios of time to distance.

Mathematics

1 answer:

storchak [24]3 years ago

4 0

Solution:

Given ratio: 12:8 = 8 + 8/2:8

This means...

Refer to table uploaded~

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4 years ago

10 points

marishachu [46]

Answer:

150+12x=630

Step-by-step explanation:

The x represents the amount of months and it is multiplied by 12 because each month costs 12$. 150 have to be paid up front and this added to the monthly fee is equal to 630$

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3 years ago

Find the perimeter of the figure to the nearest hundredth.

MariettaO [177]

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Step-by-step explanation:

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3 years ago

Alex bikes 2 3/4 miles. Then, she runs 1 2/4 miles. The distance she bikes is how many times the distance she runs?

d1i1m1o1n [39]

Answer:

2 1/5

Step-by-step explanation:

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3 years ago

Which of the following can be used to calculate the volume of water inside the fish bowl?

Lunna [17]

The volume of a sphere can be calculated as

$V=\frac{4}{3}\pi r^3$

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

$V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3$

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

$r=\frac{AB}{2}=\frac{12}{2}=6$

Let's put it into our equation

$\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\ \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}$

The problem says to use

$\pi\approx\frac{22}{7}$

Then

$V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3$

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

$V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3$

8 0

1 year ago

Enter the missing numbers in the boxes to complete the table of equivalent ratios of time to distance.​

Enter the missing numbers in the boxes to complete the table of equivalent ratios of time to distance.