Answer:
a)0.6192
b)0.7422
c)0.8904
d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Step-by-step explanation:
Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then
z(p)=
where
- Me is the margin of error from the mean
- s is the standard deviation of the population
a.
z(p)=
≈ 0.8764
by looking z-table corresponding p value is 1-0.3808=0.6192
b.
z(p)=
≈ 1.1314
by looking z-table corresponding p value is 1-0.2578=0.7422
c.
z(p)=
≈ 1.6
by looking z-table corresponding p value is 1-0.1096=0.8904
d.
Minimum required sample size for 0.95 probability is
N≥
where
- z is the corresponding z-score in 95% probability (1.96)
- s is the standard deviation (50)
- ME is the margin of error (8)
then N≥
≈150.6
Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Answer:
C) 29x=5
reason:
first, distribute the parentheses
this will make your equation 8-20x=6-3+9x
simplify to get 8-20x=3+9x
add 20x to both sides to get 8=3+29x
subtract 3 from both sides to get 5=29x
Answer:
6 hours 26 minutes
Step-by-step explanation:
Answer:
The width of the football field is 160 feet.
The length of the football field is 360 feet.
Step-by-step explanation:
Let w represent width of the football field.
We have been given that the length is 200 ft more than the width, so the length of the field would be 
.
We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:
Let us solve for w.
Therefore, the width of the football field is 160 feet.
Upon substituting in expression , we will get length of field as:
Therefore, the length of the football field is 360 feet.
Answer:
For x^2 + 5x - 14 = 0
x1= -7, x2 = 2
For x^2 + 5x + 6 = 0
x1 = -3, x2 = -2
Step-by-step explanation:
Pls see attached....
