Question

Wale was twice as old as Ajay 10 years back. How old is Ajay today if Wale will be 40 years old 10. years hence?​

Answer 1

Based on the system of equations, it is found that Ajay is 25 years old today.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

Based on the given information, we can say

Let Wale's age be x

Let Ajay's age be y

Ten years ago,

Wale = x - 10

Ajay = y - 10

If wale was twice as old as Ajay 10 years back, then;

x - 10 = 2(y - 10)

Since Wale will be 40 years old in 10 years, then;

x + 10 = 40

x = 40 - 10

x = 30

Recall that x - 10 = 2(y - 10)

30 - 10 = 2(y - 10)

20 = 2(y-10)

y = 20

Hence Ajay will be 20 years old today

Learn more on system of equation here: brainly.com/question/847634

Answer 2

Using a system of equations, it is found that Ajay is 25 years old today.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

• Variable x: Wale's age.

• Variable y: Ajay's age.

Wale was twice as old as Ajay 10 years back, hence:

$x - 10 = 2(y - 10)$

$x - 10 = 2y - 20$

$x = 2y - 10$

Wale will be 40 years old in 10 years, hence:

$x + 10 = 40$

$x = 40$

Then, Ajay's present age is found as follows.

$2y = x + 10$

$2y = 40 + 10$

$y = \frac{50}{2}$

$y = 25$

You can learn more about system of equations at brainly.com/question/14183076