Jenny jogs every five days and shannon jogs every six days. They both started jogging on tuesday of this week.

Which of the following does not represent an attribute of the function f(x) = |x|?.

zzz [600]

There are different kinds of attributes. The option that is not represent an attribute of the function f(x) = |x| is that the graph has a line of symmetry at y = 0.

Note that:

f(x) = IxI

IxI = x if x ≥ 0

IxI = -x if x ≤ 0.

<h3>Why is the statement false</h3><h3 />

The graph has a line of symmetry at y = 0." is false because the real line of symmetry is at x = 0, y = 0 is in line with the x-axis. Therefore as the graph opens up, we would not be able to have symmetry on any line parallel to the x-axis.

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2 years ago

It can be inferred that the alternative approach to measuring happiness that is most different from the current approach is base

stich3 [128]

Answer:

duplicatehttps://brainly.com/question/12705391https://brainly.com/question/12705391https://brainly.com/question/12705391https://brainly.com/question/12705391vvvv

Explanation:

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3 years ago

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Assuming ideal solution behavior, how many liters of hcl gas, measured at 30. 0 °c and 745 torr, are required to prepare 1. 25 l

Nostrana [21]

The volume of HCl gas required to prepare the solution is 101.54 L

<h3>How to determine the mole of HCl </h3>

Volume of solution = 1.25 L
Molarity = 3.20 M
Mole of HCl =?

Mole = Molarity x Volume

Mole of HCl = 3.2 × 1.25

Mole of HCl = 4 moles

<h3>How to determine the volume of HCl </h3>

Number of mole (n) = 4 moles
Temperature (T) = 30 °C = 30 + 273 = 303 K
Pressure (P) = 745 torr = 745 / 760 = 0.98 atm
Gas constant (R) = 0.0821 atm.L/Kmol

Volume =?

Using the ideal gas equation, the volume of the HCl gas can be obtained as follow:

PV = nRT

Divide both side by P

V = nRT / P

V = (4 × 0.0821 × 303) / 0.98

V = 101.54 L

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3 years ago

Determine the empirical formula of a compound containing 47. 37 grams of carbon, 10. 59 grams of hydrogen, and 42. 04 grams of o

Effectus [21]

Considering the definition of empirical formula, the empirical formula is C₃H₈O₂ and the molecular formula is C₉H₂₄O₆.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, you have:

Carbon (C): 47.37 grams
Hydrogen (H): 10.59 grams
Oxygen (O): 42.04 grams

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

Carbon (C): $\frac{47.37 grams}{12 \frac{g}{mole} }$ = 3.95 moles
Hydrogen (H): $\frac{10.59 grams}{1 \frac{g}{mole} }$ = 10.59 moles
Oxygen (O): $\frac{42.04 grams}{16 \frac{g}{mole} }$ = 2.63 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Carbon (C): $\frac{3.95 moles}{2.63 moles }$ = 1.5
Hydrogen (H): $\frac{10.59 moles}{2.63 moles }$ = 4
Oxygen (O): $\frac{2.63 moles}{2.63 moles }$ = 1

Finally, since in the empirical formula the numbers of moles must be expressed in whole numbers, the ratio of atoms is multiplied by some number with which everything is obtained in simple whole numbers (in this case by 2):

Carbon (C): 1.5× 2= 3
Hydrogen (H): 4× 2= 8
Oxygen (O): 1× 2= 2

Therefore the C: H: O mole ratio is 3: 8: 2

Finally, the empirical formula is C₃H₈O₂.

<h3>Molecular formula</h3>

To obtain the molecular formula you must relate its molecular weight (PMc) with the molecular weight of the empirical formula (PMfe).

PMfe= PM (C₃H₈O₂)= 76 g/mole

The molar mass of the compound (PMc) was determined to be 228.276 g/mol. Dividing this mass PMc by the molar mass of the empirical formula PMfe gives:

228.276 g/mol ÷ 76 g/mole= 3

This means that in the molecular formula there are 3 unit formulas (empirical formulas), so it is necessary to multiply the number of all atoms by 3.

Then, the molecular formula is C₉H₂₄O₆.

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