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3 years ago

PLSSSSS HELP MEEEEEEEEEEE

Mathematics

1 answer:

tankabanditka [31]3 years ago

8 0

Answer: 56 units

Solution: (in the pic below)

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there are 32 students in a class. NIne of those students are women. What percent are men? please answer fully.

Sergio039 [100]

Answer:

71.875% to be exact

Step-by-step explanation:

9- 32 = 23 and 23 % of 32 is 71.875%

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3 years ago

Read 2 more answers

What does find the constant rate of change mean?

natulia [17]

The change of the cost changes when the pounds of ham changes. When the pounds of ham is 0, it costs 0 dollars. When the pounds of ham is 3, it costs 12 dollars. The cost changes consistently with the pounds of ham. They change together. Every time the pounds of ham goes up by 3, the cost goes up by 12.

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4 years ago

Derrick earns $14 per hour working at Pizza Palace. What will Derrick's new hourly rate be after a 4.5% raise.

Tresset [83]

14x4,5÷100=0,63

14+0,63=14,63

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3 years ago

A liquid substance was left at the scene of the crime. Krisann uses a beaker that measures to the nearest tenth of a liter and f

AVprozaik [17]

4.85 <= x < 4.95 . does not intersect x > 5.No it does not need to be sent to the lab. B.
yes, since the beaker meaures to the nearest tenth of a liter , the range of the actual value is plus or minus 0.1 liters , which means there could be up to 5 liters of the substance

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3 years ago

2x^2+3x-2, a=0 How do I find the derivative?

Ghella [55]

You can use the definition:

$\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h$

Then if

$f(x) = 2x^2+3x-2$

we have

$f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2$

Then the derivative is

$\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}$

I'm guessing the second part of the question asks you to find the tangent line to f(x) at the point a = 0. The slope of the tangent line to this point is

$f'(0) = 4(0) + 3 = 3$

and when a = 0, we have f(a) = f (0) = -2, so the graph of f(x) passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

y - (-2) = 3 (x - 0)

y + 2 = 3x

y = 3x - 2

5 0

3 years ago