Write a procedure with a irative loop inside that adds the users numbers
2 answers:
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Answer:
Following are the code to this question:
#include<iostream>//declaring header file
using namespace std;
int main()//main method
{
int n= 6,j=0;//declaring integer variable
int X[n];//defining an array
for(j=0;j<=n;j++)//defining a loop for input value
cin>>X[j];//input value from the user
if(j==0) //defining if block that checks value at beginning
{
if(X[j]>=X[j+1])//defining if block to check to compare first and second value
{
cout<<"A peak is at array index "<<j<<" and the value is "<<X[j];//use print method to largest value with index number
}
}
else//defining else block
{
for(j=0;j<=n;j++)//defining for loop for compare other value
{
if(j==n-1) //use if block that checks next index
{
if(X[j]>=X[j-1])//use if block to compare value
cout<<"A peak is at array index "<<j<<" and the value is "<<X[j];//use print method to largest value with index number
}
else
{
if(X[j]>=X[j-1] && X[j]>=X[j+1])//comapre value
cout<<"A peak is at array index "<<j<<" and the value is "<<X[j];//use print method to largest value with index number
}
}
}
return 0;
}
Output:
please find the attached file.
Explanation:
In the given code, inside the main method two integer variable "n and j", is declared, in the next step, an array "x"is defined which input the value from the user end.
- In the next step, multiple if block is used, in the first if block it comapre the first and second value if it grater then it will print the value with its index number.
- In the next if block, it comapre is next value and if it grater then it will print the value with its index number.
