(06.03 MC)

Solve the Equation. <br> 6x−3(x+8)=9<br><br> x=?

Hunter-Best [27]

Answer:

x = -5

Step-by-step explanation:

Simplifying

6x + -3(x + -8) = 9

Reorder the terms:

6x + -3(-8 + x) = 9

6x + (-8 * -3 + x * -3) = 9

6x + (24 + -3x) = 9

Reorder the terms:

24 + 6x + -3x = 9

Combine like terms: 6x + -3x = 3x

24 + 3x = 9

Solving

24 + 3x = 9

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-24' to each side of the equation.

24 + -24 + 3x = 9 + -24

Combine like terms: 24 + -24 = 0

0 + 3x = 9 + -24

3x = 9 + -24

Combine like terms: 9 + -24 = -15

3x = -15

Divide each side by '3'.

x = -5

Hope this Helps

I hope this is correct

3 0

4 years ago

Read 2 more answers

The length of the longer leg of a right triangle is 20 inches more than twice the length of the shorter leg. The length of the h

Alex17521 [72]

Answer:

Step-by-step explanation:

Let x represent the length of the hypotenuse.

Let y represent the length of the the shorter leg.

Let z represent the length of the longer leg.

The length of the longer leg of a right triangle is 20 inches more than twice the length of the shorter leg. It means that

z = 2y + 20

The length of the hypotenuse is 22 inches more than twice the length of the shorter leg. It means that

x = 2y + 22

We would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore,

(2y + 22)² = y² + (2y + 20)²

(2y + 22)(2y + 22) = y² + (2y + 20)(2y + 20)

= 4y² + 44y + 44y + 484 = y² + 4y² + 40y + 40y + 400

4y² + 88y + 484 = y² + 4y² + 80y + 400

4y² + 88y + 484 = 5y² + 80y + 400

5y² - 4y²+ 80y - 88y + 400 - 484

y² - 8y - 84 = 0

y² + 6y - 14y - 84 = 0

y(y + 6) - 14(y + 6)

y - 14 = 0 or y + 6 = 0

y = 14 or y = - 6

The shorter length cannot be negative hence y = 14 inches

The length of the shorter side is 14 inches.

The length of the hypotenuse is

(2 × 14) + 22 = 50 inches

The length of the longer side is

(2 × 14) + 20 = 48 inches

7 0

3 years ago

What is the total number of digits required in numbering a book that has 1724 pages?

Reptile [31]

Answer:

5,789

Step-by-step explanation:

I got 5,789 because there are 9 one digit numbers. 1-9 -> 9x1=9. There are 90 two digit numbers. (10-99)-> 90x2=180. There are 900 three digit numbers. (100-999)-> 900x3=2700. There are 725 four digit numbers. (1000-1724)-> 724x4= 2900. Then, I added 9+180+2700+2900=5789.

In conclusion, the total number of digits required in numbering a book that has 1724 pages is 5789.

8 0

3 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

In the straightedge and compass construction of the parallel line below, which of the following reasons can you use to prove tha

Eva8 [605]

Answer:

D.

Step-by-step explanation:

Lines EG and CD are cut by transversal CF.

By construction, ∠FEG=∠FCD. These two angles are corresponding angles.

Since two corresponding angles are congruent, then lines EG and CD are parallel (by converse of the corresponding angles postulate).

Converse of the Corresponding Angles Postulate: If the corresponding angles formed by two lines and a transversal are congruent, then lines are parallel.

3 0

3 years ago