Question

How do you solve 2x-3y=-4 and x=7-3y by substitution?

Answer 1

Answer:

$(1, 2)$

Step-by-step explanation:

We can solve this system using substitution.

In this case, we can substitute 7-3y for x, as they are of equal value.

Therefore...

$2x-3y=-4\\2(7-3y)-3y=-4\\14-6y-3y=-4\\14-9y=-4$

Subtract 14 from both sides:

$-9y=-18$

Divide both sides by -9

$y=2$

Now, substitute 2 for y to solve for x:

$x=7-3y=7-3(2)=7-6=1$

Therefore the solution to this system of equations is:

$(x, y)=(1, 2)$