The fifth square root as in a^(1/2)^(1/2)^(1/2)^(1/2)^(1/2)
Well that is equal to a^((1/2)^5) or a^(1/32)
Since a=x^16 in this case and the rule (b^a)^c=b^(a*c) we have:
(x^16)^(1/32)
x^(16/32)
x^(1/2) or if you prefer
√x
Answer:
Domain: -1, 1, 2
Range: 3, 4, 6
Step-by-step explanation:
The domain is all of the x-values and the range is all of the y-values.
Hope this helps :)
Answer:
[-7, ∞ )
Step-by-step explanation:
I'm assuming that the function is y = (x + 8)² - 7
To find the range, we need to find the vertex,
Vertex form of a quadratic equation is y = a(x - h)² + k, where (h, k) is the location of the vertex. Our equation has a = 1, h = -8, and k = -7. Since a > 0, the parabola opens up, so the upper limit of the range is infinity. To find the lowest value of the range, we find the vertex.
Here the vertex is at point (-8, -7), so -7 is the lower limit of the function's range.
The range is [-7, ∞ )
42/2=21 (is the sum of both lengths)
2x+11=21
2x=10
x=5
length= 16
width=5
Answer:
x = 69 degrees
Step-by-step explanation:
180 - 146 = 34
180 - 77 - 34 = 69
x = 69 degrees