Subtract 89 from -42. k=-131
Answer:
1.96 planes
Step-by-step explanation:
The computation of the number of planes is shown below:
As we know that
System Inventory is
= Flow rate in the system × Throughput time
where,
Flow rate is
= Frequency of taken off
= 16 planes ÷ hour
= 16 ÷ 60 Planes per minute
Throughput time is
= runway waiting time + runway Run time
= 33 seconds + 6 minutes × 60 seconds + 48 seconds
= 441 seconds
= 441 per 60 seconds
Therefore the number of planes is
= 1.96 planes
Answer:
We do not have enough evidence to accept H₀
Step-by-step explanation:
Normal Distribution
size sample = n = 64 (very small sample for evaluating population of 5 years
Standard deviation 4,8
1.- Test hypothesis
H₀ null hypothesis ⇒ μ₀ = 14 and
Hₐ alternative hypothesis ⇒ μ₀ ≠ 14
2.- z(c) we assume α = 0,05 as we are dealing with a two test tail we should consider α/2 = 0.025.
From z table we the z(c) value
z(c) = 1.96 and of course by symmetry z(c) = -1.96
3.- We proceed to compute z(s)
z(s) = [ ( μ - μ₀ ) /( σ/√n) ] ⇒ z(s) = - (1.5)*√64/4.8
z(s) = - 2.5
We compare z(s) and z(c)
z(s) < z(c) -2.5 < -1.96 meaning z(s) is in the rejection zone
we reject H₀ .
From the start we indicate sample size as to small for the experiment nonetheless we found that we dont have enough evidence to accept H₀
I used desmos online.
(1,-2)
