Answer: I don’t know the song but I’ll check it out!
Explanation:Have a great day!✌
I would have to go with social learning
Hope this helps
Answer:
16.4 cm/0.4 ms
Explanation:
1: We know that the travel rate is 410 meters per second. We want to find a way in which we can cancel meters or seconds, and we can do that by multiplying 410m/1s with 100 cm/1m.
2. Now we want to get rid of that s, seconds, and we do so by multiplying prior fractions by 1s/1000ms.
3. Now we can diagnollay cross out m, and s. Leaving us with cm on top, and ms on the bottom. Which is what we want because we are calculating how many cm are for every .04 ms.
4: After that, you can multiply 410 and 100, to get 4,100. Whih leaves you with 4,100cm over 1000ms. Simplifying this, gives you 41, but that is NOT your answer. 41 cm, is for every ms, NOT every .04
5. Hence, you multiply 41 by .04 and get 16.4cm/.04ms.
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Answer: arrange a number of given straight-chain alkanes in order of increasing or decreasing boiling point or melting point.
arrange a series of isomeric alkanes in order of increasing or decreasing boiling point.
explain the difference in boiling points between a given number of alkanes.
Explanation:Table 3.5.1 describes some of the properties of some straight-chain alkanes.
There is not a significant electronegativity difference between carbon and hydrogen, thus, there is not any significant bond polarity. The molecules themselves also have very little polarity. A totally symmetrical molecule like methane is completely non-polar, meaning that the only attractions between one molecule and its neighbors will be Van der Waals dispersion forces. These forces will be very small for a molecule like methane but will increase as the molecules get bigger. Therefore, the boiling points of the alkanes increase with molecular size.
For isomers, the more branched the chain, the lower the boiling point tends to be. Van der Waals dispersion forces are smaller for shorter molecules and only operate over very short distances between one molecule and its neighbors. It is more difficult for short, fat molecules (with lots of branching) to lie as close together as long, thin molecules.
The boiling points shown are for the "straight chain" isomers of which there is more than one. The first four alkanes are gases at room temperature, and solids do not begin to appear until about C17H36 , but this is imprecise because different isomers typically have different melting and boiling points.
