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3 years ago

Help me I pay you guys

Mathematics

1 answer:

Eva8 [605]3 years ago

8 0

Answer:

20 degree angle

Step-by-step explanation:

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What is (3/5) squared?

Marat540 [252]

3/5 squared in 9/25, 3*3/5*5 :)

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3 years ago

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Use the data you’ve found up to this point to fill in the final column

Svet_ta [14]

The value c is 19.2

The value d is 160-x

Explanation:

To find the value of c, we need to subtract the original value and the removed value.

Thus,

c = Original - Removed

Let us substitute the value of original and removed from the table.

Thus,

$c = 19.2-0=19.2$

Thus, the value of c is 19.2

To find the value of d, we need to subtract the original value and the removed value.

Thus,

d = Original - Removed

Let us substitute the value of original and removed from the table.

Thus,

$d=160-x$

Thus, the value of d is 160-x

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3 years ago

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igor_vitrenko [27]

what is the question.......

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3 years ago

Find LCM x⁴-y⁴,x²-y² and x³-y³

Fynjy0 [20]

Answer:

Step-by-step explanation:

1st expression: x⁴-y⁴

= (x²)² - (y²)²

= (x² +y²)(x² -y²)

= (x² +y²)(x +y)(x -y)

= (x +y)(x -y)(x² +y²)

2nd expression: x² -y²

= (x +y)(x -y)

3rd expression: x³ -y³

= (x -y)(x² +xy +y²)

Now ,

Lowest Common Multiples (L.C.M.) = common factors * rest factors

= (x+y)(x-y) * (x² +y²)(x² +xy +y²)

= (x² -y²)(x²+y²) * (x² +xy +y²)

= (x⁴ -y⁴)(x² +xy +y²)

8 0

3 years ago

The surface area of a cylinder is increasing at a rate of 9 pi square meters per hour. The height of the cylinder is fixed at 3

Alekssandra [29.7K]

Answer:

$9\pi \text{ cubic meters per hour}$

Step-by-step explanation:

Since, the surface area of a cylinder,

$A= 2\pi r^2 + 2\pi rh$ ................(1)

Where,

r = radius,

h = height,

If $A= 36\pi\text{ square meters}, h = 3\text{ meters}$

$36\pi = 2\pi r^2 + 2\pi r(3)$

$18 = r^2 + 3r$

$\implies r^2 + 3r - 18=0$

$r^2 + 6r - 3r - 18 = 0$ ( by middle term splitting )

$r(r+6)-3(r+6)=0$

$(r-3)(r+6)=0$

By zero product property,

r = 3 or r = - 6 ( not possible )

Thus, radius, r = 3 meters,

Now, differentiating equation (1) with respect to t ( time ),

$\frac{dA}{dt}= 4\pi r\frac{dr}{dt} +2\pi(r\frac{dh}{dt} + h\frac{dr}{dt})$

∵ h = constant, ⇒ dh/dt = 0,

$\frac{dA}{dt} = 4\pi r \frac{dr}{dt} +2\pi h \frac{dr}{dt}$

We have, $\frac{dA}{dt}=9\pi\text{ square meters per hour}, r = h = 3\text{ meters}$

$9\pi = 4\pi (3) \frac{dr}{dt}+2\pi (3)\frac{dr}{dt}$

$9\pi = (12\pi + 6\pi )\frac{dr}{dt}$

$9\pi = 18\pi \frac{dr}{dt}$

$\implies \frac{dr}{dt} =\frac{1}{2}\text{ meter per hour}$

Now,

Volume of a cylinder,

$V=\pi r^2 h$

Differentiating w. r. t. t,

$\frac{dV}{dt}=\pi ( r^2 \frac{dh}{dt}+h(2r)\frac{dr}{dt})=\pi ((3)(6) (\frac{1}{2})) = 9\pi \text{ cubic meters per hour}$

6 0

3 years ago