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sladkih [1.3K]
2 years ago
12

Please help guys this khan and litteraly have this unit test please guys illl mark brainliest

Mathematics
2 answers:
Inessa [10]2 years ago
7 0
16/1 * 4/9 = 64/9, or 9 1/7
tankabanditka [31]2 years ago
6 0

Answer:

x=36

Step-by-step explanation:

So, lets go over what we know:

16 is equal to 4/9ths of x.

As a equation, this looks like:

16 = \frac{4}{9}x

We can begin to solve for x by multiplying both sides by the denominator, 9, which gets us:

16*9 = 4x

=

144 = 4x

Then we can divide by the coefficent of x, which is 4, to get our answer:

\frac{144}{4} = x

=

36=x

This is our answer! Hope this helps! :3

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2.A family dines in a popular franchise restaurant. They plan to use a coupon that will give them a discount of 15% off of their
Flura [38]
34 x .15 = 5.10
they would save $5.10
3 0
3 years ago
How is the function related to its parent function? Graph the function by translating the parent function.
AleksAgata [21]

y = x² is the parent function.

This is a parabola, with minimum turning point at (0, 0 ) and axis of symmetry the y- axis

y = x² - 5

is the graph of x² translated  5 units vertically down ( indicated by - 5 )

with minimum turning point at (0, - 5 )




8 0
3 years ago
Which answer choice shows 4 + 0.3 + 0.09 written in standard form?A.43.9B.4.39C.0.439D.0.0439
Oliga [24]

Place values:

As each is in a different place value, when we add them neither will affect the other, meaning:

4+0.3+0.09=4.39

Answer: B 4.39

5 0
1 year ago
John always wears a shirt, pants, socks, and shoes. He owns
Ostrovityanka [42]

Answer:

900 different combinations.

Step-by-step explanation:

He always where a shirt, pant, a pair of socks, and a pair of shoes. This type of question is asking for the amount of different ways he can wear the outfits. To do so, simplify just multiply all the numbers together:

12 x 3 x 5 x 5 = 36 x 25 = 900

There are 900 different combinations he can wear.

~

5 0
4 years ago
I just need some help solving this question, i’m not sure what to do
KonstantinChe [14]

From the double-angle identity,

cos2x=2*sinx*cosx

we can rewritte our given equation as:

4sinxcosx-2cosx=0

By factoring 2cosx on the left hand side, we have

2cosx(2sinx-1)=0

This equation has 2 solutions when

\begin{gathered} cosx=0\text{ ...\lparen A\rparen} \\ and \\ 2sinx-1=0\text{ ...\lparen B\rparen} \end{gathered}

From equation (A), we obtain

x=\frac{\pi}{2}\text{ or }\frac{3\pi}{2}

and from equation (B), we have

\begin{gathered} sinx=\frac{1}{2} \\ which\text{ gives} \\ x=\frac{\pi}{6}\text{ or }\frac{5\pi}{6} \end{gathered}

On the other hand, we can find one more solution from the original equation by substituting x=0, that is,

\begin{gathered} 2ccos(2\times0)-2cos0=0 \\ which\text{ gives} \\ 2\times1-2\times1=0 \\ so\text{ 0=0} \end{gathered}

then, x=0 is another solution. In summary, we have obtained the following solutions:

\begin{gathered} x=0 \\ x=\frac{\pi}{2}\text{or}\frac{3\pi}{2}\text{ and } \\ x=\frac{\pi}{6}\text{or}\frac{5\pi}{6} \end{gathered}

However, the intersection of the last set is empty. So the unique solution is x=0 as we can corroborate on the following picture:

Therefore, the solution set is: {0}

7 0
1 year ago
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