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Setler [38]
2 years ago
15

Find K by evaluating Limit

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
6 0

Answer:

4

Step-by-step explanation:

\lim_{x \to \infty}\frac{1-cos4x}{1-cos2x}= \lim_{x \to 0} \frac{(1-cos4x)'}{(1-cos2x)'}= \lim_{x \to 0}\frac{4sin4x}{2sin2x}= \lim_{x \to 0}\frac{2*2sin2xcos2x}{sin2x}\\ = \lim_{x \to 0}4cos2x\\ =4

{L'Hospital's rule}

<em>I hope this helps you</em>

<em>:)</em>

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