No, if x=1 then you get an undefined statement
if you want to try to simplify then
x^2-3x+2=(x-1)(x-2)
((x-1)(x-2))/(x-1)=x-2 is that true?
x-1 cancels out
x-2=x-2
true
but, the x-1 is trickey
if x=1, then the denomenator becomes 0 and the equation is undefined
undefined =x-2 is false
answer if no
but if your teacher says that it is true because of simplification tell that x=1 doesn't work
A) Basketball and Football
B) Soccer
C) ???
<h2>
For a = 1 and b = 10 x+1 and x+2 factors of x³-ax²-bx-8 = 0</h2><h2>
Other factor is (x-4)</h2>
Step-by-step explanation:
We have
x³-ax²-bx-8 = 0
Its factors are x+1 and x+2
That is x = -1 and x = -2 are its roots
Substituting x = -1
(-1)³-a(-1)²-b(-1)-8 = 0
-1 - a + b - 8 = 0
b - a = 9 ---------------------eqn 1
Substituting x = -2
(-2)³-a(-2)²-b(-2)-8 = 0
-8 - 4a + 2b - 8 = 0
2b - 4a = 16 ---------------------eqn 2
eqn 1 x -2
-2b + 2a = -18 ---------------------eqn 3
eqn 2 + eqn 3
-2a = -2
a = 1
Substituting in eqn 1
b - 1 = 9
b = 10
For a = 1 and b = 10, x+1 and x+2 factors of x³-ax²-bx-8 = 0
The equation is x³-x²-10x-8 = 0
Dividing with x + 1 we will get
x³-x²-10x-8 = (x+1)(x²-2x-8)
Dividing (x²-2x-8) with x + 2 we will get
x²-2x-8 = (x+2)(x-4)
So we have
x³-x²-10x-8 = (x+1)(x+2)(x-4)
Other factor is (x-4)
Ummmmmmmmmm 7 i think that is the wright answer
m∡A = 70º
1) Considering that the Sum of the interior angles within a triangle is always 180º
2) We can write the following, and solve for x
x+80 + x +80 +40 = 180
2x +160 +40 = 180
2x + 200 = 180
2x =180-200
2x= -20
x=-10
3) So since angle A = x +80, we can plug it into that the value of x
m∡A = x +80º
m∡A=-10+80
m∡A = 70º
