You start with f(x)=8-3(3)². Then, going in order of PEMDAS, you start with your exponent. So you have f(x)=8-3(9). Then multiplication, f(x)=8-27. Then your subtraction. f(x)=-19
Put the problem into a proportion to make it easier to solve.
32 x
=
16 100
You can use cross products to simplify this proportion. Multiply 32 by 100, and set that number equal to 16 *x.
Your equation should now look like this
3200=16x
You are trying to get the variable alone on one side, so you should divide both sides by 16.
If this is performed correctly, then your final answer should be
x=200.
It will take you 200 minutes (3 hours 20 mins) to read the pages that you promised Ms. Williams
Answer 28.
Possible values for the three factors of -3
- 1, -1 and 3
- -1.5, 1 and 2
- 1.5, -1 and 2
- 1.5, 1 and -2
Answer 29.
The product of two nonzero integers will be less than or equal to both of the integers if they are multiplied by number itself and one or by number itself and one with negative sign.
Answer 30.
The sign of the product of three integers with the same sign will be positive or negative. If odd number of same sign is multiplied, the product will be of that sign.
(+) (+) (+) = (+)
(-) (-) (-) = (-)
Answer:
Alison wins against Kevin by 0.93 s
Step-by-step explanation:
Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration
, we have the following equation of motion

where s (m) is the total distance, ta = 3 s is the time


Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration
, we have the following equation of motion:

tk = 4 s is the time


Since
we can conclude that
, so Alison would win.
The time it takes for Alison to cover the entire track



The time it takes for Kevin to cover the entire track



So Alison wins against Kevin by 6.93 - 6 = 0.93 s
Since we don't know how much students there is going to be, let's assume it's x. 367x+1500=16600. 16600-1500=15100. We have to isolate x by itself so 15100/367 which equals 41.14etc And round it to 41 since there can't be a decimal of a student. Hope this helped.