2 years ago

How to find x in a quadrilateral

Mathematics

1 answer:

evablogger [386]2 years ago

6 0

X = 360 - (122+58+58)
x = 360 - 238
x = 122

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Answer: Our required equation will be

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Since we have given that

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$(y-y_0)=\frac{y_2-y_1}{x_2-x_1}(x-x_0)\\\\(y-465)=\frac{625-465}{7-5}(x-5)\\\\(y-465)=80(x-5)\\\\y-465=80x-400\\\\y-80x=-400+465\\\\y-80x=65$

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Savatey [412]

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