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BartSMP [9]
2 years ago
6

Determine if the two figures are congruent and explain your answer using transformations.

Mathematics
1 answer:
IRISSAK [1]2 years ago
7 0

Answer:

Comparing each pair of lines,

AB and EF,

BC and FG,

CD and GH,

DA and HE.

For, AB and EF,

If we take a look at both the lines they are the mirror image of each other, the distance between point A and B is 1 unit upwards, and 2 unit sidewise, similarly between point E and F the distance is 1 unit upwards, and 2 unit sidewise. therefore, the length of both the lines is the same.

Also, we can use the formula, for the distance between two points on a coordinate plane,

,

As we can see in the image,

A = (-1, 1),

B = (-3, 2),

C = (-4, 4),

D = (-2, 6),

E = (2, 0),

F = (4, 1),

G = (5, 3),

H = (3, 5),

Solving using the formula,

AB = EF = √5,

BC = FG = √5,

CD = GH = √8,

DA = HE = √26,

Therefore, the length of all the sides of the polygon are the same,

Hence, the two figures are congruent.

Step-by-step explanation:

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An empty can weighs 30 grams. The weight of the same can filled with liquid is 47.3 grams. Which equation could be used to find
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Answer:

w = y - x is the equation to find w

Where,

w = Weight of the liquid

x = Weight of the empty can

y = Weight of the can with liquid

Step-by-step explanation:

Let

Weight of the empty can = x

Weight of the liquid = w

Weight of the can with liquid = x + w = y

x= 30 grams

w = ?

y= 47.3 grams

y = x + w

w = y - x

= 47.3 - 30

= 17.3

w= 17.3 grams

Therefore, the weight of the liquid is 17 .3 grams

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3 years ago
D square=3h+s<br>change of subject formula<br>make h the leader<br>​
Ksju [112]

Answer: h=(D²-s)/3

Step-by-step explanation: D² =3h+s

Subtract a from both sides of the equation

D²-s =3h+s-s

Simplifying,

D²-s =3h

Divide both sides by 3( to isolate 'h')

(D²-s)/3 =3h/3

Simplifying,

(D²-s)/3 =h

Hence, h= (D²-s)/3

Hope it helps!

7 0
3 years ago
Evaluate the series 4 sigma n=1 n+4
musickatia [10]

Answer:

\sum _{n=1}^4n+4=26

Step-by-step explanation:

 Given : \sum _{n=1}^4\:n+4

We have to evaluate the sum.

 

Consider , the given sum \sum _{n=1}^4\:n+4

Apply the sum rule, \sum a_n+b_n=\sum a_n+\sum b_n    

we have,

=\sum _{n=1}^4n+\sum _{n=1}^44

Consider \sum _{n=1}^4n first,

Applying sum formula, \sum _{k=1}^nk=\frac{1}{2}n\left(n+1\right)

Here, n = 4, we get,

=\frac{1}{2}\cdot \:4\left(4+1\right)

\sum _{n=1}^4n=10

Now consider \sum _{n=1}^44

\mathrm{Apply\:the\:Sum\:Formula:\quad }\sum _{k=1}^n\:a\:=\:a\cdot n

=4\cdot \:4=16

Therefore, =\sum _{n=1}^4n+\sum _{n=1}^44=10+16=26

Thus, \sum _{n=1}^4n+4=26

6 0
4 years ago
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What is 1/8 divided 3
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Answer:

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Step-by-step explanation:

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