The distance of sparky to the fire is 99.445 feet
<h3>Application of SOH CAH TOA identity</h3>
Given the following parameters
The angle of depression = 6 degrees
If Sparky is looking over the fairly level, hence the hypotenuse is 100 foot
Required
Distance from spark tower to the fire
Using the expression below
Cos 6 = D/100
D = 100cos6
D = 100(0.9945)
D = 99.45foot
Hence the distance of sparky to the fire is 99.445 feet
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Answer:
The length is 15 yards
Step-by-step explanation:
Given
Represent the width with W and length with L: So
Required
Determine the length of the rectangle:
Area is calculated as thus:
Substitute 3W - 12 for L and 135 for Area
Reorder:
Divide through by 3
Expand:
or
or
But width can't be negative
So:
Recall that:
<em>Hence, the length 15 yards</em>
Answer:
200 students must agree to attend in order for the school to have the festival.
Step-by-step explanation:
200 is 40% of 500. We can also use fractions to figure this out.
For 100 to become 500 it must be multiplied by 5. And whatever we do to the denominator we have to do to the numerator. So we multiply 40 × 5 = <em>x</em>
<em>x</em> = 200