Suppose 400 mothers will receive a gift. Predict how many will receive flowers or plants.

Sin y+ cos y + tan y sin y=sec y+ cos y tan y?

vovangra [49]

Answer:

sec y

Step-by-step explanation:z

8 0

3 years ago

A ball bearing has mass 0.44 pounds. 1 kg = 2.2 pounds. <br>

torisob [31]

Answer:

(i) 0.2 kg

(ii) kg/cm³

(b) 2.29 kg

Step-by-step explanation:

This problem gives you relations between units, and the formulas for density and mass. It is asking you to make use of these relations in various mass and density calculations.

The relationship between kg and pounds can be used to write a units conversion multiplier. It will have numerator equal to denominator, but will have units such that multiplying by it will give the units you want.

0.44 pounds × multiplier = __ kg

0.44 pounds × (1 kg)/(2.2 pounds) = (0.44/2.2)(1 kg)

0.44 pounds = 0.2 kg

__

The formula can be used to find the units of interest:

Density = mass/volume

units of density = (units of mass)/(units of volume)

units of density = kg/cm³

__

Using the given formula with the given value of L, we find the volume to be ...

V = 4(1.40 cm)(3 -1.40 cm)² = 14.336 cm³

Then the mass is ...

mass = volume × density

mass = (14.336 cm³)×(0.160 kg)/(1 cm³) = 2.29376 kg

The mass is about 2.29 kg.

_____

<em>Additional comment</em>

Often you will see density in terms of kg/m³ or g/cm³. Water has a density of about 1 g/cm³ or 1000 kg/m³. The most dense non-radioactive element in the periodic table is osmium, with a density of about 22.6 g/cm³, or 0.0226 kg/cm³. The material in part (b) of this problem has a density about 7 times that, so is clearly not from Earth.

7 0

2 years ago

On the first day of the fun raiser, the principal announces one more goal over the loud speaker- the teachers' fundraising goal.

Aliun [14]

Mabye the goal is to make the most money

7 0

4 years ago

A company manufactures aluminum mailboxes in the shape of a box with a half-cylinder top. The company will make 1960 mailboxes t

MaRussiya [10]

Answer:

7088 m²

Step-by-step explanation:

The area of the half-cylinder is half the area of a cylinder with the same dimensions. This half-cylinder has a radius of 0.3 m and a length of 0.8 m, so its area is ...

A = πr(r +l) = π(0.3 m)(0.3 m+0.8 m) = 0.33π m² ≈ 1.0362 m²

The area of the bottom part of the box is the sum of its lateral area and its base area.

lateral area = Ph = (2(0.6m +0.8m))(0.75 m) = 2.1 m²

base area = lw = (0.8 m)(0.6 m) = 0.48 m²

The total area is then ...

total area = half-cylinder area + lateral area + base area

= 1.0362 m² +2.1 m² +0.48 m²

= 3.6162 m²

__

The area for 1960 mailboxes will be 1960 times this area, or ...

area for week's production = 1960 × 3.6162 m² = 7087.752 m²

It will take about 7088 square meters of aluminum to make these mailboxes.

5 0

3 years ago

Find the volume and surface area of the composite figure. Give your answer in terms of π.

irakobra [83]

Answer:

V = 240π cm^3 , S= 168π cm^2

Step-by-step explanation:

The given figure is a combination of hemi-sphere and a cone

<u>Volume:</u>

For volume

r = 6 cm

h = 8 cm

$Volume\ of\ cone = \frac{1}{3}\pi r^2h\\= \frac{1}{3}\pi (6)^2*8\\=\frac{1}{3}\pi *36*8\\=\frac{288}{3}\pi\\=96\pi cm^3 \\\\Volume\ of\ hemisphere = \frac{2}{3}\pi r^3\\=\frac{2}{3}*\pi * (6)^3\\=\frac{2}{3}*\pi *216\\=\frac{432}{3}\\=144\pi cm^3 \\\\Total\ Volume= Volume\ of\ cone + Volume\ of\ hemisphere\\= 96\pi +144\pi \\=240\pi cm^3$

<u>Surface Area:</u>

For this particular figure we have to consider the lateral area of the cone shape and surface area of the hemisphere

We have to find the lateral height

$l = \sqrt{r^2+h^2}\\ l = \sqrt{(6)^2+(8)^2} \\l= \sqrt{36+64}\\ l = \sqrt{100}\\l = 10cm\\\\Surface\ area\ of\ cone = \pi rl\\= \pi (6)(10)\\=\pi *60\\=60 \pi\ cm^2\\\\Surface\ area\ of\ hemisphere = 2\pi r^2\\= 2 \pi * (6)\\= 2 \pi *36\\= 72 \pi\ cm^2\\\\Total\ surface\ Area = Surface\ area\ of\ cone + Surface\ area\ of \ hemisphere\\= 60 \pi + 72 \pi\\=132 \pi\ cm^2$

Hence the first option is correct ..

3 0

3 years ago