All categories

2 years ago

Using the distributive property, which expression is equivalent to 6(g + 3)?

Mathematics

1 answer:

const2013 [10]2 years ago

8 0

Step-by-step explanation:

Property: $a(b+c)=ab+ac$

<u />

<u>Use the Distributive Property:</u>

<u /> $6(g+3) =6(g)+6(3)=6g+18$

6g + 18 is an equivalent expression when the distributive property is used.

You might be interested in

Here is Diya's work writing the expression 6 - 2x + 5 + 4x with fewer terms. Describe the mistake that Diya made.

Rom4ik [11]

Answer:

Below.

Step-by-step explanation:

This is the correct solution:

6 - 2x + 5 + 4x

= -2x + 4x + 6 + 5

= 2x + 11.

It looks like they added unlike terms together (4x + 5) to give 9x (incorrect) then added the 4x to give 13x.

3 0

2 years ago

The formula to convert °F to °C is C = 5/9 (F – 32).

k0ka [10]

I don’t know the question isn’t making any sense at least to me

5 0

3 years ago

What’s the area? For this

ZanzabumX [31]

to figure out the area you have to use the formula 1/2 base times height.

7 0

2 years ago

In her piggy bank, caitlin has 5.24 dollars the sum is made up of an equal number of four coins from 1 cent, 5 cents, 10 cents,

Ludmilka [50]

Answer:

1c, 5c, 25c and 1 dollar

Step-by-step explanation:

With 4 coins of 1c : 4 cents

4 coins of 5c: 20 cents

4 coins of 25c: 1 dollar

4 coins of 1 dollar: 4 dollars

So, 4c + 20c + 1 dollar + 4 dollars = 5.24 dollars

3 0

3 years ago

Triangle J is shown below. James drew a scaled version of Triangle J using a scale factor of 4 and labeled it

Novay_Z [31]

Answer:

The area of triangle K is 16 times greater than the area of triangle J

Step-by-step explanation:

we know that

If Triangle K is a scaled version of Triangle J

then

Triangle K and Triangle J are similar

If two triangles are similar, then the ratio of its areas is equal to the scale factor squared

Let

z -----> the scale factor

Ak ------> the area of triangle K

Aj -----> the area of triangle J

$z^{2}=\frac{Ak}{Aj}$

we have

$z=4$

substitute

$4^{2}=\frac{Ak}{Aj}$

$16=\frac{Ak}{Aj}$

$Ak=16Aj$

therefore

The area of triangle K is 16 times greater than the area of triangle J

4 0

2 years ago

Read 2 more answers