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2 years ago

5

angle a and angle b are supplementary angles. if m angle a = (7x+14)° and m angle b =( 5x-26)°, then find the measure of angle b

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1 answer:

Allisa [31]2 years ago

8 0

Answer: 54 degrees

Step-by-step explanation:

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Question 4 i need help on!!

MrMuchimi

Answer:

C 20

Step-by-step explanation:

Set up equations:

Laguna's Truck Rentals

y = 2x + 20

Where x is the number of miles driven and y is the total price

<em>How did we get to this equation?</em>

Well, the company charges $2 for every mile driven. Therefore, by multiplying 2 and x, you will find the price paid per mile. The 20 (which represents $20) is the one-time payment you pay for simply using the service.

Salvatori's Truck Rentals

y = 3x

Where x is the number of miles driven and y is the total price

<em>How did we get to this equation?</em>

For this company, you only pay for how many miles you drive. There isn't a one-time payment like there is for Laguna's Truck Rentals. Therefore, you only need to multiply the price per mile ($3) by the number of miles driven (x).

Set the equations equal to each other:

2x + 20 = 3x

<em>Why would you do this?</em>

We need to set the equations equal to each other because we need to find the point at which the prices are the same. When two things are the same, they are equal. Therefore, we get rid of the y variable (which represents the total price) because we want to find the value of x when the equations are equal to one another.

Solve:

2x + 20 = 3x

Subtract 2x on both sides:

2x + 20 = 3x

-2x -2x

20 = x

When x is equal to 20, or when the number of miles driven is 20, the total price of the Truck Rental services is the same.

Hope this helps :)

4 0

2 years ago

cylinder A has a radius of 6 centimeters cylinder B has the same height and a radius half as long as cylinder A what fraction of

REY [17]

Volume of a cylinder=the area of the base multiply the height
Cylinder A's volume: pi*6*6*h=36*pi*h
Cylinder B's volume: pi*3*3*h=9*pi*h
so the fraction is 9/36=1/4
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6 0

3 years ago

How much cashews at $1.58 per pound must be mixed with walnuts that cost 78 cents per pound to make a mixture of 40 pounds of nu

Likurg_2 [28]

Number of pounds of cashews is 36 pounds and number of pounds of walnuts is 4 pounds.

Step-by-step explanation:

Step 1: Given details are cost of cashews = $1.58, cost of walnuts = 78 cents = $0.78, total weight of nuts = 40 pounds, cost of nuts per pound = $1.50

Step 2: Let number of pounds of cashews to be mixed be C, then number of pounds of walnuts will 40 - C. Form equation with these variables.

⇒ 1.58 C + (40-C) 0.78 = 40 × 1.50

⇒ 1.58 C + 31.2 - 0.78 C = 60

⇒ 1.58 C - 0.78 C = 60 - 31.2

⇒ 0.8 C = 28.8

⇒ C = 36 pounds

Step 3: Calculate number of pounds of walnuts

⇒ Number of pounds of walnuts = 40 - C = 4 pounds

5 0

3 years ago

Read 2 more answers

In triangle EFG, angle E equals 8x-16, angle F equals x+8, and angle G equals 2x-10. What is the value of x?

Stels [109]

Answer: The value of x= 18

Step-by-step explanation:

Given: In triangle EFG, angle E equals 8x-16, angle F equals x+8, and angle G equals 2x-10.

The sum of all angles of a triangle is 180°.

Therefore, in triangle EFG

∠E + ∠F +∠G= 180°

⇒ 8x-16 +x+8+ 2x-10 = 180

⇒ 11x-18= 180

⇒ 11x = 180+18

⇒11x=198

⇒ x= 18 [Divide both sides by 11]

Hence, the value of x= 18

6 0

2 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

<em>On integration , we get</em>

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

= $\frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6$

on calculation , we get

= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0

2 years ago