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2 years ago

I accidentally forgot how to calculate height pls help! im in 6th grade btw

Mathematics

1 answer:

lozanna [386]2 years ago

8 0

1: 9 1/3

2: 12 1/2

3: 14 3/4

Step-by-step explanation:

A=BH

H=A/B

B=A/H

B = Base

H = Height

A = Area

Hope this help!

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Question is in the picture

Leviafan [203]

Answer: d,f

$-x\geq 4\\=> x\leq -4$

=> all the values are d and f

Step-by-step explanation:

5 0

2 years ago

Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec

julia-pushkina [17]

Answer:

$(2,6,6) \not \in \text{Span}(u,v)$

$(-9,-2,5)\in \text{Span}(u,v)$

Step-by-step explanation:

Let $b=(b_1,b_2,b_3) \in \mathbb{R}^3$ . We have that $b\in \text{Span}\{u,v\}$ if and only if we can find scalars $\alpha,\beta \in \mathbb{R}$ such that $\alpha u + \beta v = b$ . This can be translated to the following equations:

1. $-\alpha + 3 \beta = b_1$

2. $2\alpha+4 \beta = b_2$

3. $3 \alpha +2 \beta = b_3$

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for $\alpha,\beta$ and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

$-\alpha + 3 \beta = 2$

$2\alpha+4 \beta = 6$

whose unique solutions are $\alpha =1 = \beta$ , but note that for this values, the third equation doesn't hold (3+2 = 5 $\neq$ 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

$-\alpha + 3 \beta = -9$

$2\alpha+4 \beta = -2$

whose unique solutions are $\alpha=3, \beta=-2$ . Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0

2 years ago

Number ten please thanks

BlackZzzverrR [31]

-3^2= -(3)^2

The exponent of 2 only applies to the number 3. -(3)^2 should equal -9. This is true because according to the order of operations, exponents should be evaluated before multiplication. The negative sign here represents -1* 3^2.
If you want to find -3 to the power of 2 it must be written (-3)^2.

5 0

2 years ago

Simplify and she the steps how to solve this (5t^2 + 4) - (6t^2 - 7t + 1)

torisob [31]

Answer:

11t² + 7t + 3

Step-by-step explanation:

⇒ (5t² + 4) - (6t² - 7t + 1)

⇒ 5t² + 4 - 6t² + 7t - 1

⇒ 11t² + 7t + 3

4 0

2 years ago