The parameters of the normal distribution of the thermometer readings are its mean and the standard deviation
The probability that a thermometer reading is between 99.86o F and 100.07o F is 0.5403
<h3>The sketch of the normal distribution of the thermometer</h3>
The given parameters are:
- Mean, μ = 100
- Standard deviation, σ = 0.15
Next, we draw the normal distribution using a graphing calculator.
See attachment for the sketch of the normal distribution of the thermometer
<h3>The probability that a thermometer reading is between 99.86o F and 100.07o F</h3>
This means that:
x = 99.86 and x = 100.07
The probability is calculated as:
P(99.86 < x < 100.07) = P(x > 99.86) - P(x < 100.07)
Using the attached graph, we have:
P(99.86 < x < 100.07) = 0.5403
Read more about normal distribution at:
brainly.com/question/4079902
Answer:
-56
Explanation:
From the equation:
0.75(x + 20) = 2 + 0.5(x - 2)
Open brackets
0.75x + 15 = 2 + 0.5x - 1
Collect like terms
0.75x - 0.5x = 2 - 1 - 15
0.25x = - 14
Divide both sides by 0.25
x = -56
The label match up are:
- dark fur
- more individuals with darker fur
- dark rocks and light rocks
- dark fur and light fur
- rocks of intermediate color
- more individuals with intermediate fur color
<h3>What is a phenotype?</h3>
A person's Phenotype is known to be those detectable qualities or traits of their genotype.
Looking at the image, the label match up are:
- dark fur
- more individuals with darker fur
- dark rocks and light rocks
- dark fur and light fur
- rocks of intermediate color
- more individuals with intermediate fur color
Learn more about phenotypes from
brainly.com/question/902712
#SPJ1
If you got a 680 SAT score, you're probably wondering how you compare to other students, and whether a 680 is good enough to get into college.
The truth is, it depends on your personal college goals and where you want to apply.
Note: this 680 score guide is for the New SAT, out of 1600. This score corresponds to a 870 in the old SAT out of 2400.
Answer:
a) 92.30=26m+0.3t
b) 221 texts
Explanation:
If we plug in 1 for the month variable we get
92.30=26+0.3t
subtract 26 from both sides and we get 66.3=0.3t
Divide by 0.3 and we get t=221