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2 years ago

A projectile is projected from the origin with a velocity of 30

SAT

1 answer:

Sliva [168]2 years ago

6 0

For this we will use kinematic equations.

We need the time of flight to compute the range.

With the given information, the most useful formula is:

Δy=v0yt−g2t2

Because our equation is taking only vertical motion into account,

v0y=30sin(45)

Because we are looking for the range of the object,

Δy=0

This leaves us with only one unknown: t

0=30sin(45)t−g2t2

g2t2=30sin(45)t

g2t=30sin(45)

t=60gsin(45)

For horizontal distance, the formula we need is:

Δx=v0xt

Because we are taking into account the horizontal range,

v0x=30cos(45)

In substituting our derived values into the equation we can see that:

Δx=30cos(45)∗60gsin(45)

Range=30cos(45)∗60gsin(45)

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A tortoise and a hare engage in a race. A tortoise can run with a speed of 0. 15 m/s. A hare can run 25 times as fast as the tor

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After these 300 seconds, the remaining time for the tortoise to complete the race is (T - t - 300 s). In this same time, the hare loses the race by 35 cm = 0.35 m, so overall it has covered a total distance of

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Solve for T :

(3.75 m/s) t + 0 + (3.75 m/s) T - (3.75 m/s) t - 1125 m = D - 0.35 m

(3.75 m/s) T - 1125 m = D - 0.35 m

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