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2 years ago

What is the range of the radical function f(x) = to the square root of x-2 +4

Mathematics

1 answer:

jarptica [38.1K]2 years ago

6 0

Answer:

2,∞

Step-by-step explanation:

For the range, x2 takes its minimum at x=0 , so putting in x =0 gives y=√x2+4=√0+4=2 therefore making the range [2,∞).

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The function y= sin 2 (x - 1/2) has a period of?

Evgen [1.6K]

Answer:

I believe the period is 1. Because if it was y= sin2 (2(x-1/2) then the period would be 2.

5 0

2 years ago

HELP ASAP PLZ!!!!!!!!!!!!!! THANKS IN ADVANCED :)

taurus [48]

I think its the 30x + 20

4 0

3 years ago

Find the real or imaginary solutions of each equation by factoring

anyanavicka [17]

Sum of 2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so

x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4

the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$
for x²-4x+16=0
x= $\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(16)} }{2(1)}$
x= $\frac{4+/- \sqrt{16-64} }{2}$
x= $\frac{4+/- \sqrt{-48} }{2}$
x= $\frac{4+/- (\sqrt{-1})(\sqrt{48}) }{2}$
x= $\frac{4+/- (i)(4\sqrt{3}) }{2}$
x= $2+/- 2i\sqrt{3}$

the roots are
x=-4 and 2+2i√3 and 2-2i√3

8 0

3 years ago

The following data set represents the age of

Julli [10]

$\huge\text{Hey there!}$

$\huge\textsf{Breaking the meaning down in simpler terms}$
$\huge\textbf{Median:}\\\large\text{is understood to be \bf the number in the center (also known as}\\\large\textbf{the middle number)}$

$\huge\textbf{Mean:}\\\large\text{is understood to be the \bf total.}$

$\huge\textsf{Formulas for each term}$

$\huge\text{Median:}\\\large\textsf{To find the median you have to put each of your numbers in your data}\\\large\textsf{set from LEAST (smallest) to GREATEST (biggest). }$

$\huge\text{Mean:}\\\mathsf{\dfrac{sum\ of\ all\ terms}{number\ of\ terms}= mean}$

$\huge\textbf{SOLVING FOR THE QUESTION}$

$\huge\textsf{Median:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textbf{Conversion: }\large\text{27, 33, 38, 41, 42, 52, 64, 68, 72}\\\\\large\textsf{Make sure it is even between both sides of the data plot.}\\\\\large\text{It seems to even on BOTH sides of \boxed{\textsf{14}} so it could possibly be your}\\\large\text{median.}$

$\huge\textsf{Mean:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textsf{Your equation: }\mathsf{\dfrac{27 + 52 + 64 + 41 + 33 + 38 + 42 + 60 +72 + 68}{10}}\\\\\mathsf{\dfrac{79 + 64 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{143 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{184 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{217 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{255 + 42 + 60 + 72 + 68}{10}}$

$\mathsf{\dfrac{297 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{357 + 72 + 68}{10}}\\\\\mathsf{\dfrac{429 + 68}{10}}\\\\\mathsf{\dfrac{497}{10}}\\\\\mathsf{\approx 49.70}\\\\\large\text{From the looks of it \boxed{\rm{\dfrac{497}{10}}}\ or \boxed{\text{49.70}} could possibly be your mean.}$