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igomit [66]
2 years ago
5

Which transformations will produce similar, but not congruent, figures?

Mathematics
2 answers:
kotykmax [81]2 years ago
7 0
Answer: Choice D

The reason why is because any time you have a dilation with a scale factor other than 1, then the resulting figure is either bigger or smaller compared to the original. If two figures of the same shape are different sizes, then they cannot be congruent. The other transformations of rotation, reflection and translation are what we call rigid transformations. They preserve the size leading to keeping the figures congruent. 
miskamm [114]2 years ago
6 0

Answer:

hello the answer is choice D

Step-by-step explanation:

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Answer:

V=πr6^2h /3

Step-by-step explanation:

8 0
3 years ago
What is A- 3.5= 14.9
gladu [14]
A = 14.9 +3.5 = 18.4 :D

7 0
2 years ago
Please Help!!
expeople1 [14]

A = P(1 + rt)

Where:

<span>·         </span>A = Total Accrued Amount (principal + interest)

<span>·         </span>P = Principal Amount

<span>·         </span>I = Interest Amount

<span>·         </span>r = Rate of Interest per year in decimal; r = R/100

<span>·         </span>R = Rate of Interest per year as a percent; R = r * 100

<span>·         </span>t = Time Period involved in months or years

A = 15,000(1+ 0.07(5))

A = 20,250 they acquired in total for 5 years

The yearly amount the get is 15,000 xx 0.07 = $ 1050 per year

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7 0
3 years ago
–5(3 – q) + 4 = 5q – 11
mrs_skeptik [129]

Answer:

0

Step-by-step explanation:

–5(3 – q) + 4 = 5q – 11

-15 +5q + 4 = 5q -11

-11 + 5q = 5q - 11

+5q - 5q = -11 + 11

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6 0
3 years ago
A pilot flew a 400 mile flight in 2.5 hours flying into the wind. Flying the same rate and with the same wind speed the return t
eduard

Answer: 20 mph

Explanation:

Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):

v=\frac{d}{t}

In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:

v-w=\frac{400mi}{2.5h}=160 mph (1)

During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:

v+w=\frac{400 mi}{2 h}=200 mph (2)

So we have two equations with two unknown variables. From (1), we get

v=160+w

Substituting into eq.(2)

(160+w)+w=200\\160+2w=200\\2w=40\\w=20 mph

So, the speed of the wind was 20 mph.

3 0
2 years ago
Read 2 more answers
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