Answer:
f(5) = 13
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Function notation and substitution
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = x² - 12
x = 5
<u>Step 2: Evaluate</u>
- Substitute: f(5) = 5² - 12
- Exponents: f(5) = 25 - 12
- Subtract: f(5) = 13
Answer:
3/10
Step-by-step explanation:
3/5 se puede convertir en 6/10
(3x2)/(5x2).
9/10 - 6/10 = 3/10
le falta 3/10 para llegar a 9/10.
the equation would be y = 30 + x and if your brother will read for 15 minutes then you'll read for 45 minutes i believe.
h(x) = 3 * (2)^x
Section A is from x = 1 to x = 2
h(1) = 3 * (2)^1 = 3 * 2 = 6
h(2) = 3 * (2)^2 = 3 * 4 = 12
so
the average rate of change = (12 - 6)/(2 - 1) = 6
Section B is from x = 3 to x = 4
h(3) = 3 * (2)^3 = 3 * 8 = 24
h(4) = 3 * (2)^4 = 3 * 16 = 48
so
the average rate of change = (48 - 24)/(4 - 3) = 24
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)
the average rate of change of section B is 24 and the average rate of change of section A is 6
So 24/6 = 4
The average rate of change of Section B is 4 times greater than the average rate of change of Section A
It's exponential function, not a linear function; so the rate of change is increasing.
3 yrs ago:
Alice - x
Jane - 3x
Fast forward 2 years... 1 year ago:
Sum of their ages = 62
Equation to solve: x + 3x = 62
4x = 62
----- -----
4 4
x = 15.5
From this, we can deterime that Alice is 15 1/2 years old.
Then, plug in 15.5 for x in 3x to find Jane's age.
15.5 × 3 = 46.5
From this, we can determine that Jane is 46 1/2 years old.
I hope this helps you to understand this problem better.
