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Kazeer [188]
2 years ago
8

What is an equation of the line that passes through the points (5,-3) and (-3, -3)?

Mathematics
2 answers:
andreyandreev [35.5K]2 years ago
6 0

Answer:

y=-3

Step-by-step explanation:

First, you want the slope.

The slope is

\frac{-3-(-3)}{-3 - 5} = \frac{0}{-8}\\

0/-8 = 0, so the line is horizontal.

the y-intercept must be -3 because it never changes.

So the equation must be

y=-3

Bogdan [553]2 years ago
5 0
  • (5,-3)
  • (-3,-3)

Slope:-

\\ \rm\hookrightarrow m=\dfrac{-3+3}{-3-5}=0

Equation of line in point slope form

\\ \rm\hookrightarrow y+3=0(x-5)

\\ \rm\hookrightarrow y+3=0

\\ \rm\hookrightarrow y=-3

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The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

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CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

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Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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