To solve this problem you must apply the fomrula for calculate the area of a cylinder, which is shown below:
A=2πrh+2πr^2
Where r is the radius and h is the height of the cylinder
You have that r=15.1 inches and h=12.8 inches, then:
A=2πrh+2r^2
A=2π(15.1 in)(12.8 in)+2π(15.1 in)^2
A=2647 in^2
The answer is 2647 in^2
Answer:
d
Step-by-step explanation:
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Maximizing the Area of a rectangle. Drag the locators to vary the width of the rectangle and see the effect on its area. For a rectangle with a perimeter of 40, the height is always 20 minus the width. This allows you to reduce the formula for the area. I hope this helps you
Answer:
- x² - 8x + 12
- x³ + 2x² - 15x - 36
- x³ -2x² - 15x
Step-by-step explanation:
#1) Find the polynomial with roots at 2 and 6
-
(x -2)(x - 6) = x² - 8x + 12
#2) Find the polynomial with a double root at -3 and another root at 4
-
(x+3)(x+3)(x-4) = (x²+6x+9)(x-4) = x³ + 2x² - 15x - 36
#3) Find the polynomial with roots 0, -3 and 5
- (x -0)(x+3)(x-5) = x(x²-2x - 15) = x³ -2x² - 15x
Answer:
Given : ∠ABC is a right angle, ∠D BC is a straight angle.
To prove :∠AB D is a right angle.
Proof: ∠ ABC = 90°[ Given]
∠ D BC= 180° [ D BC is a straight line]
now, ∠ AB D and ∠ AB C are adjacent angles forming linear pair.
∠ AB D +∠ AB C =180° [By linear pair axiom]
⇒∠ AB D + 90= 180°
⇒∠ AB D=180°-90°
⇒∠ AB D=90°
∠AB D is a right angle
Hence proved.
