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2 years ago

If A=1/2bxh, find A when b=4.5 and h=5.2

Mathematics

1 answer:

zhenek [66]2 years ago

8 0

Answer:

A = 11.7

Step-by-step explanation:

Just substitute the known values into the equation:

$A=\frac{1}{2}(4.5)(5.2)\\A=11.7$

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Find the remainder when f(x) is divided by (x - k). <br><br> f(x) = 8x4 + 7x3 + 5x2 - 5x + 35; k = 4

Slav-nsk [51]

Using the remainder theorem, evaluating the function for k will be the same value as the remainder.
8(4^4) + 7(4^3) + 5(4^2) -5(4) + 35 =
2048 + 448 + 80 + - 20 + 35 =
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3 years ago

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4)Rudy collects baseball cards, and he currently has 300 cards. Starting tomorrow, he will purchase 1 pack of 15 baseball cards

andre [41]

I think it’s answer B

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3 years ago

The Alvin Secretarial Service procures temporary office personnel for major corporations. They have found that 60% of their invo

Hoochie [10]

Answer:

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

Step-by-step explanation:

For each invoice, there are only two possible outcomes. Either they are paid within 10 working days, or they are not. The probability of an invoice being paid within 10 working days is independent of other invoices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

60% of their invoices are paid within ten working days.

This means that $p = 0.6$

A random sample of 18 invoices is checked.

This means that $n = 18$

What is the probability that at least 6 of the invoices will be paid within ten working days?

Either less than 6 are paid within 10 working days, or at least 6 are paid. The sum of the probabilities of these events is 1. So

$P(X < 6) + P(X \geq 6) = 1$

We want $P(X \geq 6)$ . So

$P(X \geq 6) = 1 - P(X < 6)$

In which

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{18,0}.(0.6)^{0}.(0.4)^{18} \approx 0$

$P(X = 1) = C_{18,1}.(0.6)^{1}.(0.4)^{17} \approx 0$

$P(X = 2) = C_{18,2}.(0.6)^{2}.(0.4)^{16} \approx 0$

$P(X = 3) = C_{18,3}.(0.6)^{3}.(0.4)^{15} = 0.0002$

$P(X = 4) = C_{18,4}.(0.6)^{4}.(0.4)^{14} = 0.0011$

$P(X = 5) = C_{18,5}.(0.6)^{5}.(0.4)^{13} = 0.0045$

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0 + 0 + 0 + 0.0002 + 0.0011 + 0.0045 = 0.0058$

Finally

$P(X \geq 6) = 1 - P(X < 6) = 1 - 0.0058 = 0.9942$

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

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3 years ago

What are the factors of the square root of 329

Andru [333]

Answer: $x=-\dfrac{3}{2}, 7$

Step-by-step explanation:

$2x^2-10x-26=x-5$

$2x^2-10x-26-x+5=0$ Move all terms to one side

$2x^2-11x-21=0$ Simplify $2{x}^{2}-10x-26-x+5$

$2x^2+3x-14x-21=0$ Split the second term

$x(2x+3)-7(2x+3)=0$ Factor out common terms in the first two terms, then in the last two terms.

$(2x+3)(x-7)=0$ Factor out the common term $2x+3$

$x=-\dfrac{3}{2}, 7$

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Mamont248 [21]

Answer:

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Step-by-step explanation:

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3 years ago