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steposvetlana [31]
2 years ago
14

HELP ME FOR 30 P!!!!!!

Mathematics
2 answers:
lyudmila [28]2 years ago
6 0

Answer:D

Step-by-step explanation: x-coordinate is same ( from picture), but height is different(y)

Radda [10]2 years ago
4 0

Answer:

OPTION D.

Step-by-step explanation:

Given:-

An image of house in the graph.

To find which option is correct.

So here we can notice that the roof top and the right side of the door is on a same straight line.

And it lies in the first co-ordinate.

So in the first coordinate in a straight line the value of x is always the same and only the value of y increase or decrease.

So here the correct option is OPTION D.





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BlackZzzverrR [31]
<h3>Answer:  Choice C.   |x+3| < 5</h3>

=======================================================

Explanation:

Let's go through each answer choice and solve for x

----------------------------------------------------------------------

Choice A

|x+3| < -5

This has no solutions because |x+3| is never negative. It is either 0 or positive. Therefore, it can never be smaller than -5. So we can rule this out right away.

----------------------------------------------------------------------

Choice B

|x+8| < 2

-2 < x+8 < 2 .... see note below

-2-8 < x+8-8 < 2-8 ... subtract 8 from all sides

-10 < x < -6

We will have a graph where the open circles are at -10 and -6, with shading in between. This does not fit the original description. So we can rule this out too.

----------------------------------------------------------------------

Choice C

|x+3| < 5

-5 < x+3 < 5 .... see note below

-5-3 < x+3-3 < 5-3 .... subtracting 3 from all sides to isolate x

-8 < x < 2

We found our match. This graph has open circles at -8 and 2, with shading in between. The open circles indicate to the reader "do not include this value as a solution".

----------------------------------------------------------------------

note: For choices B and C I used the rule that |x| < k turns into -k < x < k where k is some positive number. For choice A, we have k = -5 which is negative so this formula would not apply.

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I am just not sure if I did this properly. My professor hasn't really gone over when to use the range equation but I would assume range would equal the distance traveled therefore can be used for this problem. If not the how would I go about solving this? I did 1/6*9.8=1.63 for g on the moon Then used R=(Vi^2sin2theta)/g so on the moon R=((28^2)sin2*35)/1.63=452m

Please Brainliest..? thx

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