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2 years ago

12

The coordinates of the point V are (3,-10) and the coordinates of point W are (3,-3). What is the distance, in units, between th

e point V and point W?

1 answer:

Zolol [24]2 years ago

4 0

Answer:

I

Step-by-step explanation:

werwewr

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Is (10 – 3) – 2 = 10 – (3 –) correct?

dusya [7]

Answer: No solution

Step-by-step explanation:

(10–3)–2=10–(3–)

10−3−2=10−3, this is false so it is not correct, and the answer for the equation is no solution.

6 0

3 years ago

I need help with this please its due today :(

yKpoI14uk [10]

Answer:

$a) \ 6^2 \times 6^3 = 6^{2+3} = 6^5 = 7776\\\\b)\ \frac{(-3)^5 }{(-3)^2} = (-3)^{5-2} = (-3)^3 = -27\\\\c)\ [(-2)^3]^4 = (-2)^{3\times 4} = (-2)^{12} = 4096 \\\\d)\ (\frac{1}{999})^0 = 1, anything \ raise \ to \ zero = 1\\\\e) \ (\frac{4}{3})^{-2} = 4^{-2} \times 3^2 = \frac{9}{16}\\\\f) \ \frac{2^5 \times 2^9}{2^{16}} = 2^{5+9-16} = 2^{-2} = \frac{1}{4}$

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2 years ago

Two functions are shown below function A and function B HURRY PLSSS (100 POINTS)

almond37 [142]

Answer:

Im sorry but the other 2 answers are cut off, I think it's B)

Step-by-step explanation:

4 0

1 year ago

Read 2 more answers

Find the range of the function for the given domain, f(x)=3x+3; (-2,-1,0,1,2)

stich3 [128]

Answer:

Range: (-3,0,3,6,9)

Step-by-step explanation:

We need to evaluate each value in the domain of the function, so

f(-2)=3(-2)+3=-6+3=-3

f(-1)=3(-1)+3=-3+3=0

f(0)=3(0)+3=0+3=3

f(1)=3(1)+3=3+3=6

f(2)=3(2)+3=6+3=9

8 0

3 years ago

first 33.25 was divided by some number. the resulting quotient was then multiplied by 7. following this 5.9 was subtracted

dimaraw [331]

(33.25/x)*7-5.9. ....

6 0

3 years ago