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1 year ago

What is the elapsed time between 8:00 a.m and noon ?

Mathematics

2 answers:

nikitadnepr [17]1 year ago

7 0

4 hours because noon is 12. 8-12 is 4

andriy [413]1 year ago

6 0

Answer:

Four Hours

Step-by-step explanation:

Noon is equivalent to 12:00pm

This is how I would usually do that in my head and counting on my fingers:

8am to 9am is one hour.

9am to 10 am is one hour.

10am to 11am is one hour.

11am to 12pm is one hour.

Add those hours together and you get four hours.

Alternatively, 12-8=4 so four hours.

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Help, 100 pts + brainlist for first person to answer

Blababa [14]

Answer:

About 4.

Step-by-step explanation:

It is actaully 3.95 but if you were rounding and in fraction form, it would be four! Hope this helps!

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1 year ago

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Which triangles are similar by the angle-angle criterion for similarity of triangles ?

Alex Ar [27]

Answer:

Option D is correct.

$\triangle ADE \sim \triangle ABC$

Step-by-step explanation:

In triangle ADE and triangle ABC

From the figure:

$\angle ADE = \angle ABE$ [Angle] [Given]

$\angle DAE = \angle BAC$ [Angle]

AA(Angle-Angle) similarity criterion states that in two triangles if two pairs of corresponding angles are equal, then these triangle Similar.

By AA similarity:

⇒ $\triangle ADE \sim \triangle ABC$

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2 years ago

Which is the least expensive per oz? 12 oz for $5.28 or 18 oz for $7.96. round to the nearest cent?

blondinia [14]

5.28 / 12 = 0.44 per oz
7.96 / 18 = 0.4422 rounds to 0.44 per oz

technically, by rounding to the nearest cent, they are the same cost.

6 0

2 years ago

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Sketch a cylinder with radius 8 feet and height 3 feet, then find the volume.

4vir4ik [10]

Answer: 339.29ft^3

Step-by-step explanation:

The formula for a cylinder is πr^2h

In your scenario, r=8 and h=3 so put those into the equation -

π8^2(3) and just solve!

7 0

2 years ago

Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the

zlopas [31]

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

$\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}$

$\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}$

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

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2 years ago